To answer this question we need to first get the slope of the line 5x-4y=9 by rearranging it in the form of y=mx+b: 5x-4y=9 4y=5x-9 y=(5/4)x-9/4 Since the slope of parallel lines are negative reciprocals of each other, the negative reciprocal of 5/4 is -4/5, therefore the slope of a line parallel to the line 5x-4y=9 is -4/5
Point Slope Form - Y=.5X+1.5
Transform the equation into slope-intercept form: y = mx + b. The intercept is b. 5x - 4y = 18 -4y = 18 - 5x 4y = 5x - 18 y = 5x/4 - 18/4 so the y-intercept is -18/4 or -4.5
If: y = 2/5x+10 then the perpendicular slope is -5/2x or -2.5x
12
To answer this question we need to first get the slope of the line 5x-4y=9 by rearranging it in the form of y=mx+b: 5x-4y=9 4y=5x-9 y=(5/4)x-9/4 Since the slope of parallel lines are negative reciprocals of each other, the negative reciprocal of 5/4 is -4/5, therefore the slope of a line parallel to the line 5x-4y=9 is -4/5
5x+4y = -3 4y = -5x-3 y = -5/4 x - 3 Slope is -5/4.
5x + 4y = 204y = -5x + 20y = (-5/4)x + 5
It is a straight line equation which in slope intercept form is: y = 1.25x+0.25
dy/dx = 5/4
5x+4y = 20 4y = -5x+20 y = -5/4x+5 Therefore: slope is -5/4 and intercept is 5
4y=-5x-12 your slope would be -5/4 your new slope intercept form would be y=-5/4x-3
5x-4y=8
5x+4y = -4 4y = -5x -4 y = -5/4x -1 or as y = -1.25x -1 both of which are in slope-intercept form
5x + 4y = -2Subtract 5x from each side:4y = -5x - 2Divide each side by 4:y = -1.25 x - 0.5In this form, we can look at it and see that the slope of the graph is -1.25and the y-intercept is -0.5 .
Point Slope Form - Y=.5X+1.5
Transform the equation into slope-intercept form: y = mx + b. The intercept is b. 5x - 4y = 18 -4y = 18 - 5x 4y = 5x - 18 y = 5x/4 - 18/4 so the y-intercept is -18/4 or -4.5