If: y = 2/5x+10 then the perpendicular slope is -5/2x or -2.5x
the slope is in front of the x when solved for y.y=2x-3The slope is 2.
Get y by itself in standard form y = mx + b where m = slope and b = y intercept 2x + 4y - 10 = 0 4y = -2x +10 y = -2/4 x + 10/4 y = -1/2 x + 2.5 slope = - 1/2
3x + 2y = -14 is correct. Line L has slope 2 3 , so use slope - 3 2 * and the given point to apply the point-slope formula. our welcome mizz litta bay be aka anhellita richards
They determine the equation of a nonvertical line in the slope-intercept form, y = 3x - 10.
It has infinite slope.
10 is.
If: y = 2/5x+10 then the perpendicular slope is -5/2x or -2.5x
2x+y = 10 or y = -2x + 10 so the slope is -2
-1 (negative 1)
the slope is in front of the x when solved for y.y=2x-3The slope is 2.
5y - x = 10 5y = x + 10 or y = x/5 + 2 This is now the equaltion of the line in the standard form and the slope of the line is the coefficieint of x that is, 1/5 or 0.2
A line with the equation:x = a constant valueis a vertical line. Examples of such a line are x = 3, x = 5, x = 10, x = -4.The slope of a vertical line is infinite.
It has infinite slope.
Answer:-10/2=-5Solution:The relation between the line slope and it's perpendicular line slope is negative reciprocal, i.e.Slope of the line perpendicular = -1/Slope of the line= -1/(2/10)= -1 x 10/2= -10/2= -5
It is a straight line equation which can be rearranged to y = 3x+10 in slope intercept form
a like that is parallel to the line y - 5x = 10 will have the same slope as y - 5x = 10. the slope of a line is determined by the standard form of a linear equation y = mx + b where m is the slope. we need to get our equation to look like the standard form. y - 5x = 10 y = 10 + 5x (adding 5x to both sides) comparing this to our standard form y = mx + b the number in front of the x is our slope. in this particular equation m = 5 the slope of a like parallel to this line will be the same, a slope of 5