If you mean y-5 = 6(x-4) then y = 6x-19 and using the same slope for point (4, 6) the equation is y = 6x-18 and both equations are parallel to each other.
the slope is in front of the x when solved for y.y=2x-3The slope is 2.
Which of the following is the point-slope equation of the line with a slope equals -4 and a point of -2 3?
It should be in the form of: y = mx+b whereas m is the slope and b is the y intercept
If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14
If you mean: slope of -13 and point of (5, 7) then the equation is y = -13x+72
No line described, but here is the point slope form. Y - Y1 = m(X - X1) =============
Equation of a straight line is: y = mx+c whereas m is the slope and c is the y intercept
the slope is in front of the x when solved for y.y=2x-3The slope is 2.
-5
That will depend on the value of the slope which has not been given.
Which of the following is the point-slope equation of the line with a slope equals -4 and a point of -2 3?
It should be in the form of: y = mx+b whereas m is the slope and b is the y intercept
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
35
no it is different
If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14
If you mean: slope of -13 and point of (5, 7) then the equation is y = -13x+72