what is the slope of the line below?
(-1,-4) (2.2)
2
Points: (-1, -1) and (-3, 2) Slope: -3/2
If: 11x-8y = 32 Then: -8y = -11x+32 And: y = 1.375x-4 in slope-intercept form
|32 - 132| = |-100| = 100 |32 - 132| = |-100| = 100
If you mean: 32-10x+7y = 0 then as a straight line equation it is 7y = 10x-32
It has no slope.
To find the slope of the line perpendicular to the given equation, we first need to determine the slope of the original line. The equation (-4x + 3y = -32) can be rearranged into slope-intercept form (y = mx + b). Solving for (y), we get (3y = 4x - 32) or (y = \frac{4}{3}x - \frac{32}{3}), which has a slope of (\frac{4}{3}). The slope of a line perpendicular to this would be the negative reciprocal, which is (-\frac{3}{4}).
2
Points: (-1, -1) and (-3, 2) Slope: -3/2
Points: (-1, -1) and (-3, 2) Slope: -3/2
If you mean points: (-3, -5) and (3, 2) then the slope works out as 7/6
32%
30
If: 11x-8y = 32 Then: -8y = -11x+32 And: y = 1.375x-4 in slope-intercept form
To find the slope between the points (32) and (10), we need to know their coordinates. Assuming these points are (32, y1) and (10, y2), the slope ( m ) can be calculated using the formula ( m = \frac{y2 - y1}{10 - 32} ). Without specific y-values, the slope cannot be determined. Please provide the complete coordinates for an accurate calculation.
11x-4y=32
32