To find the slope between the points (32) and (10), we need to know their coordinates. Assuming these points are (32, y1) and (10, y2), the slope ( m ) can be calculated using the formula ( m = \frac{y2 - y1}{10 - 32} ). Without specific y-values, the slope cannot be determined. Please provide the complete coordinates for an accurate calculation.
It has no slope.
To find the slope of the line perpendicular to the given equation, we first need to determine the slope of the original line. The equation (-4x + 3y = -32) can be rearranged into slope-intercept form (y = mx + b). Solving for (y), we get (3y = 4x - 32) or (y = \frac{4}{3}x - \frac{32}{3}), which has a slope of (\frac{4}{3}). The slope of a line perpendicular to this would be the negative reciprocal, which is (-\frac{3}{4}).
32
The slope is 3.(y = mx + b, m is the slope: y=3x+10)
It has infinite slope.
It has no slope.
If: 11x-8y = 32 Then: -8y = -11x+32 And: y = 1.375x-4 in slope-intercept form
11x-4y=32
To find the slope of the line perpendicular to the given equation, we first need to determine the slope of the original line. The equation (-4x + 3y = -32) can be rearranged into slope-intercept form (y = mx + b). Solving for (y), we get (3y = 4x - 32) or (y = \frac{4}{3}x - \frac{32}{3}), which has a slope of (\frac{4}{3}). The slope of a line perpendicular to this would be the negative reciprocal, which is (-\frac{3}{4}).
32
The slope is 3.(y = mx + b, m is the slope: y=3x+10)
It has infinite slope.
2
It has infinite slope.
Answer:-10/2=-5Solution:The relation between the line slope and it's perpendicular line slope is negative reciprocal, i.e.Slope of the line perpendicular = -1/Slope of the line= -1/(2/10)= -1 x 10/2= -10/2= -5
slope = change_in_y / change_in_x = (2 - -4) / (3 - 0) = 6/3 = 2
Points: (-1, -1) and (-3, 2) Slope: -3/2