The product of the slope of a line with the slope of a line perpendicular to it is -1.
Or to put it another way, if a line has an equation
y = mx + c
a line perpendicular to it will have a gradient m' such that
mm' = -1
⇒ m' = -1/m
and an equation of
y = -1/m x + b
which can be rearranged to give
my + x = d
(where d = mb).
There are symbols missing from the question, which I suspect are a plus (+) and an equals (=). They can be inserted in two different ways, leading to two different solutions:
⇒ gradient of perpendicular line is -1/-2 = 1/2
⇒ perpendicular line is:
y = 1/2 x + b
⇒ 2y = x + c
⇒ gradient of perpendicular line is -1/2 = -1/2
⇒ perpendicular line is:
y = -1/2 x + b
⇒ 2y + x = c
Note: there is no one perpendicular line, the value of the constant c will vary depending upon what point the line must pass through.
12
Get the slope of the given line, by putting it into slope-intercept form. Then you can divide minus one by this slope, to get the slope of any perpendicular line.
x - 4y = 3 is the slope of a line perpendicular to line whose equation is y -5 3x plus 8 3.
If you mean y = 2x+5 then the perpendicular slope is -1/2
If you mean: y = 5x-2 then the perpendicular slope is -1/5
12
Get the slope of the given line, by putting it into slope-intercept form. Then you can divide minus one by this slope, to get the slope of any perpendicular line.
x - 4y = 3 is the slope of a line perpendicular to line whose equation is y -5 3x plus 8 3.
If you mean y = 2x+5 then the perpendicular slope is -1/2
-5
It is: -1/2
Slope of a line = m slope of perpendicular line = -1/m
the slope will be positive 1.5x the whole equation is y=4.5+1.5x
For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )
It is -1/2
- 1/3
Without an equality sign it can't be considered to be an equation but in general if the slope was 3 then the perpendicular would be -1/3