2x+3y=12 ......1st equation
3x+2y=13 .......2nd equation
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multiplying 1stt equation by 3 and 2nd equation by 2
3x(2x+3y=12)
2x(3x+2y=13)
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now the equations become
6x+9y=36 ...3rd
6x+4y=26 ....4th
by solving both equation(substractinf 4th from 3rd) we get..
5y=10
therefore y=2
and x=3
{-1,-2}
It's an inconsistent pair of equations, for which there is no solution.
There is only one equation - possibly due to the limitations of the browser. There are not enough equations to derive a solution.
y = 0 and x = 8.
One way would be to graph the two equations: the parabola y = x² + 4x + 3, and the straight line y = 2x + 6. The two points where the straight line intersects the parabola are the solutions. The 2 solution points are (1,8) and (-3,0)
x=3
x = 1 and y = 2
That system of equations has no solution. When the two equations are graphed, they turn out to be the same straight line, so there's no such thing as a single point where the two lines intersect. There are an infinite number of points that satisfy both equations.
{-1,-2}
(0,7)
When (the graph of the equations) the two lines intersect. The equations will tell you what the slopes of the lines are, just look at them. If they are different, then the equations have a unique solution..
There are two solutions and they are: x = -1 and y = 3
Solve this system of equations. 5x+3y+z=-29 x-3y+2z=23 14x-2y+3z=-18 Write the solution as an ordered triple.
No.
It's an inconsistent pair of equations, for which there is no solution.
-10
A pair of simultaneous equations in two unknowns which are inconsistent - in the sense that there is no solution that simultaneously satisfies both equations. Graphically, the equations are those of two parallel lines (slope = 2). Since, by definition, they cannot meet there is no solution to the system.