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2x+3y=12 ......1st equation

3x+2y=13 .......2nd equation

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multiplying 1stt equation by 3 and 2nd equation by 2

3x(2x+3y=12)

2x(3x+2y=13)

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now the equations become

6x+9y=36 ...3rd

6x+4y=26 ....4th

by solving both equation(substractinf 4th from 3rd) we get..

5y=10

therefore y=2

and x=3

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Q: What is the solution to the system of equations 3x plus 2y equals 13 and 2x plus 3y equals 12?
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