represented as contiuous fraction: sqrt(163) = [12, [1, 3, 3, 2, 1, 1, 7, 1, 11, 1, 7, 1, 1, 2, 3, 3, 1, 24]] There is no real square root of 163, you would not be able to simplify it.
However, represented as a rounded decimal it is about equal to 12.7671453
Yes.
square root of (2 ) square root of (3 ) square root of (5 ) square root of (6 ) square root of (7 ) square root of (8 ) square root of (9 ) square root of (10 ) " e " " pi "
square root 2 times square root 3 times square root 8
We use the property of square roots that says the square root of (ab)=square root (a) multiplied by square root of b So square root (4x)=square root (4) mutiplies by square root of x =2(square root (x)) 2sqrt(x)
the square root of 3, the square root of 5, the square root of 6, the square root of 7, the square root of 8 etc
163 is the square root of 26569.
The square roots of 163 are irrational.
Yes.
No because it then becomes an irrational number
The square root of 163 is - approximately - 12.7671453348037 As this is a number which cannot be expressed as a fraction it is called an irrational number.
Here is how you can figure this out. Take the square root of 7581. Round this up. Square the result. This will give you the closest perfect square that is larger than 7581. Calculate the difference.
The square root of the square root of 2
The 8th root
square root of (2 ) square root of (3 ) square root of (5 ) square root of (6 ) square root of (7 ) square root of (8 ) square root of (9 ) square root of (10 ) " e " " pi "
There are infinitely many of them. They include square root of (4.41) square root of (4.42) square root of (4.43) square root of (4.44) square root of (4.45) square root of (5.3) square root of (5.762) square root of (6) square root of (6.1) square root of (6.2)
It's not a square if it has no root. If a number is a square then, by definition, it MUST have a square root. If it did not it would not be a square.
square root 2 times square root 3 times square root 8