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What is Square root of 3 plus square root of 3?
sqrt(3) + sqrt(3) = 2*sqrt(3) NOT sqrt(3 + 2)
Square root 2 times square root 3 times square root 8?
square root 2 times square root 3 times square root 8
How do you factor x squared plus x minus one half?
(x^2+x-1/2)= x(x+1)-1/2 [x + (1 - square root of 3)/2][x + (1 + square root of 3)/2] = 0 Check it: x^2 + x/2 + (square root of 3)x)/2 + x/2 + 1/4 + (square root of 3)/4 - (square root of 3)x/2 - (square root of 3)/4 - 3/4 = 0 x^2 + x/2 + x/2 + [(square root of 3)x]/2 - [(square root of 3)x]/2 + (square root of 3)/4 - (square root of 3)/4 + 1/4 - 3/4 = 0 x^2 + x - 2/4 = 0 x^2 + x - 1/2 = 0 How to find this roots: Using the completing the square method: x^2 + x - 1/2 = 0 x^2 + x = 1/2 x^2 + x + 1/4 = 1/2 + 1/4 (x + 1/2)^2 = 3/4 x + 1/2 = (plus & minus)(square root of 3/4) x = -1/2 + (square root of 3)/2 x = - 1/2 - (square root of 3)/2
Find the two numbers whose product is 1 and whose sum is 1?
x + y = 1xy = 1y = 1 - xx(1 - x) = 1x - x^2 = 1-x^2 + x - 1 = 0 or multiplying all terms by -1;(-x^2)(-1) + (x)(-1) - (1)(-1) = 0x^2 - x + 1 = 0The roots are complex numbers. Use the quadratic formula and find them:a = 1, b = -1, and c = 1x = [-b + square root of (b^2 - (4)(a)(c)]/2a orx = [-b - square root of (b^2 - (4)(a)(c)]/2aSox = [-(-1) + square root of ((-1)^2 - (4)(1)(1)]/2(1)x = [1 + square root of (1 - 4]/2x = [1 + square root of (- 3)]/2 orx = [1 + square root of (-1 )(3)]/2; substitute (-1) = i^2;x = [1 + square root of (i^2 )(3)]/2x = [1 + (square root of 3)i]/2x = 1/2 + [i(square root of 3]/2 andx = 1/2 - [i(square root of 3)]/2Since we have two values for x, we will find also two values for yy = 1 - xy = 1 - [1/2 + (i(square root of 3))/2]y = 1 - 1/2 - [i(square root of 3)]/2y = 1/2 - [i(square root of 3)]/2 andy = 1 - [1/2 - (i(square root of 3))/2)]y = 1 - 1/2 + [i(square root of 3))/2]y = 1/2 + [i(square root of 3)]/2Thus, these numbers are:1. x = 1/2 + [i(square root of 3)]/2 and y = 1/2 - [i(square root of 3)]/22. x = 1/2 - [i(square root of 3)]/2 and y = 1/2 + [i(square root of 3)]/2Let's check this:x + y = 11/2 + [i(square root of 3)]/2 +1/2 - [i(square root of 3)]/2 = 1/2 + 1/2 = 1xy = 1[1/2 + [i(square root of 3)]/2] [1/2 - [i(square root of 3)]/2]= (1/2)(1/2) -(1/2)[i(square root of 3)]/2] + [i(square root of 3)]/2](1/2) - [i(square root of 3)]/2] [i(square root of 3)]/2]= 1/4 - [i(square root of 3)]/4 + [i(square root of 3)]/4 - (3i^2)/4; substitute ( i^2)=-1:= 1/4 - [(3)(-1)]/4= 1/4 + 3/4= 4/4=1In the same way we check and two other values of x and y.
What are two numbers whose sum -6 and product is -5?
-2 and -3Check:(-2) + (-3) = -5(-2)(-3) = 6Thus -2 and -3 are not the required numbers. let's find them: x + y = -6xy = -5 y = -x -6x(-x - 6) = -5-x^2 - 6x = -5x^2 + 6x = 5x^2 + 6x + 9 = 5 + 9(x + 3)^2 = 14x + 3 = (+ & -)square root of 14x = -3 (+ & -)square root of 14x = -3 + square root of 14 or x = - 3 - square root of 14y = -x - 6y = 3 - square root of 14 - 6 or y = 3 + square root of 14 - 6y = -3 - square root of 14 or y = -3 + square root of 14Check:(-3 + square root of 14) + (-3 - square root of 14) = -6(-3 + square root of 14)(-3 - square root of 14) = -5 ?(-3)^2 - (square root of 14)^2 = -5 ?9 - 14 = -5Check also tow other numbers.
What is the square root of 3 divided by 2 plus the square root of 3 divided by 2?
2 times the Square root of 3 + 4
What is 5 times the square root of 2 plus the square root of 3 times the quantity of the square root of 2 plus 2 times the square root of 3?
if you take out the word ''quantity'' your answer is 25.02725024
What is the square root of 4 plus the square root of 9?
sqrt(4) = 2 sqrt(9) = 3 Therefore, the square root of 4 plus the square root of 9 is equal to 2 + 3 = 5.
Square root of 150 plus 3 square root of 2?
154.242641
What is the square root 2 plus 3 square root 5 Times Square root 2 minus square root 7?
24
What is Square root of 3 plus square root of 3?
sqrt(3) + sqrt(3) = 2*sqrt(3) NOT sqrt(3 + 2)
What is 2 square root of 20 - square root of 20 plus 3 square root of 20 - 2 square root 45?
It is 2*sqrt(5).
Square root of 4x plus the square root of x?
square root of 4x is 2 times square root of x, so answer is square root of x times 3 since it is 2 square roots of x plus one of them
How do you rationalize the denominator in this expression 2 divided by the square root of 3 plus the square root of 2?
Multiply everything by the square root of 3 minus the square root of 2 and then times that by 100 - 72 and divide that by 5
Square root of 24 plus 3 square root of 90 plus 2 square root 150 simplified?
It's a bit unclear what you wish done with these numbers. Possibly you are describing three different problems. Or you wish all three final numbers multiplied together into an answer. In any case: 1. The square root of 24 plus 3 is approximately equal to 7.8989794855663561963945681494118. 2. The square root of 90 plus 2 is approximately equal to 11.486832980505137995996680633298. 3. The square root of 150 is approximately equal to 12.247448713915890490986420373529.
Square root of 27 plus 2 times 3 square rooted?
5 Square root 3. square root 27 = square root 9*3 = 3square root 3 3square root3 + 2square root3 = 5Square Root3 because both have a square root 3.
What is 7 square root of 3 plus 6 square root of 3?
10 square root of 3.
