sqrt(41) cannot be simplified so it remains radical(41).
the square root of 164= 2x the square root of 41
In radical form, 3* sqrt(41). The decimal approximation is 19.20937271.
sqrt(656) = sqrt(16*41) = sqrt(16)*sqrt(41) = 4*sqrt(41)
Yes in fact the root of all prime numbers is irrational.
Irrational. The square root of a positive integer is either an integer, or an irrational number.
41
the square root of 164= 2x the square root of 41
the square root of 164= 2x the square root of 41
Oh, dude, you're hitting me with the math questions now? Like, the square root of 164 in radical form is 2√41. So, if you ever need to impress someone at a party with your knowledge of square roots, there you go.
In radical form, 3* sqrt(41). The decimal approximation is 19.20937271.
sqrt(656) = sqrt(16*41) = sqrt(16)*sqrt(41) = 4*sqrt(41)
square root of 81 is 9...and plus 32 is 41.so the answer is 41
41
41
No.
The square root of 41 is an irrational , algebraic, real number. It is real, is the root of an polynomial equation with integer coefficients, but can not be expressed as a ratio of integers.
x = 41 √x = √41 √x ≈ 6.4