The square root of 3136 is 56.
± 7.483315
No. The square root of a positive integer can only be an integer, or an irrational number.
Between 7 and 8 7 x 7 = 49 8 x 8 = 64 and 56 is between 49 and 64
What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units
in decimal form the answer is 18.7082869
The square root of 3136 is 56.
Square root of 56 = Square root of (4 x 14) = (Square root of 4) x (Square root of 14) = 2 x (Square root of 14) The actual value would be 2 x 3.741 = 7.482
± 7.483315
56
sqrt(56) = 7.483 approx.
Root 56 = 7.483314773547882 = 7.48
square root of 3136, square root 3146 56x56
"7" is the number because its square root is "49" & 49+7=56
4
No. The square root of a positive integer can only be an integer, or an irrational number.
sqrt(56)factor under the radicalsqrt(22 * 14)2 comes out from under radical2sqrt(14)==============best I can see