2 square root of 14
The square root of 3136 is 56.
± 7.483315
No. The square root of a positive integer can only be an integer, or an irrational number.
Between 7 and 8 7 x 7 = 49 8 x 8 = 64 and 56 is between 49 and 64
What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units
The square root of 56 is approximately 7.48. This value can be simplified to ( \sqrt{56} = \sqrt{4 \times 14} = 2\sqrt{14} ). Thus, while the exact square root is not a whole number, it can be expressed in this simplified radical form.
in decimal form the answer is 18.7082869
The square root of 3136 is 56.
The square root of 56 is irrational. This is because 56 can be expressed as 4 times 14, and while the square root of 4 is rational (2), the square root of 14 is not a perfect square and is therefore irrational. Thus, the combined result of √56 remains an irrational number.
No, the square root of 56 is not an integer. The square root of 56 can be simplified to 2√14, which is an irrational number. Since it cannot be expressed as a whole number, it does not qualify as an integer.
Square root of 56 = Square root of (4 x 14) = (Square root of 4) x (Square root of 14) = 2 x (Square root of 14) The actual value would be 2 x 3.741 = 7.482
sqrt(56) = 7.483 approx.
± 7.483315
56
Root 56 = 7.483314773547882 = 7.48
square root of 3136, square root 3146 56x56
"7" is the number because its square root is "49" & 49+7=56