The square root of 40 is about 6.32
The square root of 40 is an irrational number
If the positive square root (for example, square root of 2) is irrational, then the corresponding negative square root (for example, minus square root of 2) is also irrational.
Yes, as is the positive square root.
6.322=40
No - remember that you cannot have a negative square root. Instead, the square root should be +40 as opposed to -40.
The square root of 1600 is 40, therefore the square root of -1600 is 40i, where "i" is the imaginary unit.
4X10= 40 take the square root of 2 and makes exactly a 2, and just leave the square root of 10 with radical sign so the answer is 2i square root of 10
Because the Square Root of negative 1 = i (The imaginary square root of negative 1.) and where if the square root of one number and of another number are multiplied together, the answer is equal to the square root of the two numbers combined. (Square root of 8 times the square root of 5 equals the square root of 40.) So... √(-20) =√20×√(-1) =√4×√5×i =2i(√5) The answer is 2i times the square root of 5. square root (-20) = square root (-1) x square root (20) square root (-20) = i x 4.47213595 square root (-20) = 4.47213595 i
square root of a negative number is imaginary square root of negative 1 is defined as i square root of negative 144 is sqrt ((144)(-1)) = 12i
The square root of 40 is about 6.32
Square root of 40 approximately = 6.324555325 / square root of 40 = 0.790569415
The square root of negative 37 is: ~6.0827 i
The square root of negative 168 is: ~12.9315 i
The square root of a negative number is not real.
Nothing. You cannot have a square root of a negative number. The square root of negative one is called i, but i is an imaginary number. It does not exist and does not follow the properties of real numbers. (For example, if a and b are positive, then the square root of a times the square root of b is the square root of ab. But the square root of -7 is not the square root of 7 times i.)
Negative 64 is the square root of an integer. The square root of -64 is not an integer.