To find the sum of 13 and a number where their product equals 60, we must first determine the other number. We can do this by finding the factors of 60, which are 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, and 60. The pair that works in this case is 5 and 12. Therefore, the sum of 13 and 12 is 25.
There are four prime factors to 60 : 2, 2, 3, 5. All those multiplied together will give 60, as will any combinations of all those numbers. 2 x 30, 3 x 20, 4 x 15, 5 x 12 and 6 x 10
However none of those pairings can be added or subtracted so as to give 13
30 - 2 = 28
20 - 3 = 17
15 - 4 = 11
10 + 6 = 16
So I believe that if the number are to be used to make 13 in a sum and 60 in a multiplication we need to introduce a 1 into the factors.
Now we get
1 + 2 + 2 + 3 + 5 = 13
1 x 2 x 2 x 3 x 5 = 60 Alternately, 6 + 5 + 2 = 13 and 6 x 5 x 2 = 60
The numbers are: 16 and -3
The anwer is 8 and 5 and thedifference of the two is 3
10 and 3
NO!!! Product means Mu;ltiply Sum means Addition (Add).
9 and 4. 9*4=36 9+4=13
How about: 47*13 = 611 and 47+13 = 60
This question doesn't make sense. The sum of 11 and 60 is 71. The product of 11 and 60 is 660.
The product of 7 and 60 is 420. The sum of 7 and 60 is 67.
The sum of 8 and 5 is 13. There is then no number with which to calculate its product.
30.
Take 13 and 17 as an example. Sum is 13 + 17 ie 30, product is 13 x 17 = 221
6+10=16 , 60=6*10
29.
13
If the product of the two numbers is the sum times 24, then the product of the two numbers is 2400. 40 times 60 is 2400, and 40 plus 60 is 100. The two numbers are 40 and 60.
43
The answer is 12. 12x6=72 12+60=72