Best Answer

Here is the formula-

(Number of sides -2) x180 degrees = angle sum.

The sum of the interior angles inside of a polygon will be 180*(n-2) degrees, where n=number of sides of the polygon. Example: a triangle has 3 sides; therefore, the sum of the angles inside will be equal to 180*(3-2)=180*(1)=180 degrees.

Q: What is the sum of all of the angles inside a polygon?

Write your answer...

Submit

Still have questions?

Continue Learning about Algebra

The sum of the exterior angles of all polygons equals to 360⁰.Since only the sum of the interior angles of all quadrilaterals equals to 360⁰, the polygon must have 4 sides.

What is the sum of the exterior angles for a 157 sided polygon?

Sum of exterior angles = 360 degrees Sum of interior angles = 1440 degrees

All exterior angles of any polygon sum to 360 deg. If there are 9 angles then each angle is 40 degrees.

The sum of the exterior angles is always 360 degrees.

Related questions

If you multiply 360 by the number of angles in the polygon and then subtract the sum of all the interior angles you will end up with the sum of all the exterior angles of the polygon.

there r 800 vetices in three triangles

It is: ('n'-2)*180 = sum of interior angles whereas 'n' is the number of sides of the polygon

Count the number of sides = N. Then sum of all the interior angles = (N -2)*180 degrees.

Yes and it is: ('n'-2)*180 = sum of interior angles whereas 'n' is the number of sides of the polygon

The formula for finding the sum of all angles of a polygon is: N = number of sides (N-2)180 = The sum of all angles

The sum of the exterior angles of any regular polygon is 360°

The sum of the exterior angles of a polygon is 360o.

A Regular Polygon

(number of sides-2)*180+360 = total sum of interior and exterior angles of any polygon.

This has to do with the way in which the sum of the angles is derived. First you select a point inside the polygon and then join that point to each of the vertices. For a polygon with n sides, this gives rise to n triangles. The sum of the 3 angles of any triangle is 180 degrees. So the sum of the angles of all the triangles is n*180 degrees. Now, the "outer" angles of these triangles correspond to the interior angles of the polygon. But the sum also includes the angles formed arounf the central point. The sum of all the angles around this central point is 360 degrees. This is not part of the sum of the interior angles of the polygon and so must be subtracted. Thus, the interior angles of a polygon sum to n*180 - 360 degrees or 180*(n- 2) degrees.

The sum of the exterior angles of any polygon is 360 degrees.