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Here is the formula-

(Number of sides -2) x180 degrees = angle sum.

The sum of the interior angles inside of a polygon will be 180*(n-2) degrees, where n=number of sides of the polygon. Example: a triangle has 3 sides; therefore, the sum of the angles inside will be equal to 180*(3-2)=180*(1)=180 degrees.

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Q: What is the sum of all of the angles inside a polygon?
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What is the sum of the measures of the exterior angles of a polygon?

If you multiply 360 by the number of angles in the polygon and then subtract the sum of all the interior angles you will end up with the sum of all the exterior angles of the polygon.


The sum of all angles inside a polygon?

there r 800 vetices in three triangles


What is the rule for the sum of angles inside of a polygon?

It is: ('n'-2)*180 = sum of interior angles whereas 'n' is the number of sides of the polygon


How do you find the sum of all the angles inside a regular polygon?

Count the number of sides = N. Then sum of all the interior angles = (N -2)*180 degrees.


Is there a rule for the sum of angles inside a polygon?

Yes and it is: ('n'-2)*180 = sum of interior angles whereas 'n' is the number of sides of the polygon


The formula for finding the sum of the angles of a polygon?

The formula for finding the sum of all angles of a polygon is: N = number of sides (N-2)180 = The sum of all angles


What is the sum of all the exterior angles in a 6 side regular polygon?

The sum of the exterior angles of any regular polygon is 360°


Sum of exterior angles of polygon?

The sum of the exterior angles of a polygon is 360o.


If the sum of the interior angles of a polygon equals the sum of the exterior angles what is the name of the polygon?

A Regular Polygon


What is the sum of all the angles of a polygon?

(number of sides-2)*180+360 = total sum of interior and exterior angles of any polygon.


Why do you subtract 2 from n to find the sum of interior angles?

This has to do with the way in which the sum of the angles is derived. First you select a point inside the polygon and then join that point to each of the vertices. For a polygon with n sides, this gives rise to n triangles. The sum of the 3 angles of any triangle is 180 degrees. So the sum of the angles of all the triangles is n*180 degrees. Now, the "outer" angles of these triangles correspond to the interior angles of the polygon. But the sum also includes the angles formed arounf the central point. The sum of all the angles around this central point is 360 degrees. This is not part of the sum of the interior angles of the polygon and so must be subtracted. Thus, the interior angles of a polygon sum to n*180 - 360 degrees or 180*(n- 2) degrees.


Sum of angles in a polygon?

The sum of the exterior angles of any polygon is 360 degrees.