Best Answer

The answer is 1600.

All you have to do is times the number given into itself.

Example

first 50 odd numbers would be 50x 50= 2500.

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Q: What is the sum of the first 40 consecutive odd numbers?

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490,000

640000. First odd number is 1, 800th odd number is 1599, giving their sum: sum = number_of_numbers x (first_number + last_number) ÷ 2 = 800 x (1 + 1599) ÷ 2 = 640000

3 and 5

There are no such answers. The sum of even numbers is even. The sum of odd numbers could be even, but the sum of three consecutive odd numbers is always odd. One could swap the questions to get potentially answerable questions: Sum of 3 consecutive EVEN integers = 150 48 + 50 + 52 = 150 unfortunately, we can already see that if we were to make these odd integers (add 1 to each), we would get 153, not 151. Sum of 3 consecutive ODD integers = 151 49 + 51 + 53 = 153 47 + 49 + 51 = 147 We can see that, whenever we slide our three consecutive integers up one, we raise the value of the sum up 3, and if we jump from odd to odd, or even to even, we raise each integer by 2, so we raise the sum by 6.

7 and 9 72+92 = 130

Related questions

The sum of the first 350 consecutive odd numbers is 122,500.

The sum of the first 60 consecutive odd numbers is 3,600.

The sum of the first 60 consecutive odd numbers is 3,600.

The sum of the first 30 consecutive odd numbers is 900.

the sum of first 50 consecutive odd numbers is 9801

The sum of the first 30 consecutive odd numbers is 900.

The sum of the first 600 consecutive odd numbers is 360,000.

The sum of the first 900 consecutive odd numbers is 810,000.

The sum of the first 450 consecutive odd numbers is 450 squared or 202,500.

The sum of the first 250 consecutive odd numbers is 250 squared or 62,500.

The sum of the first 1,300 consecutive odd numbers is 1,300 squared or 1,690,000.

The sum of the first 60 consecutive odd numbers is 3,600.