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The sum of the interior angles of any polygon can be found with the formula

180º*(n-2)

letting n be the number of sides of the polygon.

Simply substituting 6 for n, we find that the sum of the interior angles of a pentagon is 720 degrees. Here is the work shown:

S=180º*(n-2) ---> S represents sum and nrepresents the number of sides

S=180º*(6-2) ---> There are 6 sides so n becomes 6

S=180º*4 ---> 6 subtract 2 is 4

S=720º ----> 180 multiplied by 4 is 720

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Q: What is the sum of the interior angles in a six sided polygon?
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