The sum of the exterior angles of all polygons equals to 360⁰.Since only the sum of the interior angles of all quadrilaterals equals to 360⁰, the polygon must have 4 sides.
Sum of exterior angles = 360 degrees Sum of interior angles = 1440 degrees
Any quadrilateral
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. 6660 degrees.
The sum of the interior angles would be (36-2)180 degrees=6120 degrees.
A Regular Polygon
(number of sides-2)*180 = sum of interior angles of a polygon
the sum of the interior angles of a 3 sided polygon is = 180 degrees. the sum of the interior angles of any polygon is given by 540/n. in this case n is = 3
The sum of the interior angles of an n-sided polygon is 180n - 360 degrees.
(number of sides-2)*180 = sum of the interior angles
a convex polygon has 6 sides . What is the sum of the measure of its interior angles?
It is: (n-2)*180 = sum of interior angles whereas 'n' is the number of sides of the polygon
No. In a convex polygon the sum of the interior angles is (n-2)*180 deg where n is the number of interior angles. In a non-convex polygon this is not necessarily true.
(number of sides -2)*180 = sum of interior angles.
A polygon that has a sum of 2520 degrees of interior angles has 16 sides
The sum of the interior angles of a n-sided polygon is (n-2)*180 degrees. This is true whether or not the polygon is regular.
The formula for the sum of the interior angles of a polygon is: 180 * (n - 2) where n is the number of sides of the polygon. So the sum of the angles of a polygon with 25 sides is 180 * 23 = 4,140.