If in the real number universe, first k is to be >0, y=kx = exlog(k)
the antiderivative of eax is eax/a so the antiderivative of Y
is exlog(k) / log(k) = kx /log(k)
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if f(x)=kx, f'(x)=ln(k)*kx. Therefore, the derivative of 2x is ln(2)*2x.
k + 5k = 6k 2 x 3 x k
4x-9=k 4x=k+9 Divide by 4 to isolate the x x=(1/4)k+(9/4) x=1/4 k+ 9/4
x = ¼x^4 + 4x + k where k can be any number
x to the ninth power OR x to the 9th power OR x^9