2^n = 128
hope you know logs or ln
log each side:
log2^n = log228
bring the n down (basic log rule)
nlog2 = log128
n = log128/log2
n = 7
double check 2^7 = 128
21
7
It is: 2 to the power of 7 = 128
2 to the 7th power equals 128....
2 to the power of 1 (21) equals 2.
If we take the logarithm of both sides, then it is log(4^x) = log(128). Then from logarithm rules, this can be changed to: x*log(4) = log(128), then x = log(128)/log(4). You can punch this into a calculator and get the answer, but what if we use log base 2, we don't need a calculator. So log2(4) = 2, because 2² = 4. And log2(128) = 7, because 2^7 = 128. So we have x = 7/2 = 3.5, then you can check your answer: 4^3.5 = (4^3)*(4^.5). So 4 cubed = 64, and 4 raised to the 1/2 power is the square root of 4, which is 2. So 64 times 2 = 128.
The best estimate is the true value.512 = 2^9 = 2^7*2^2 = 128*4Then 512*25 = (128*4)*25 = 128*(4*25) = 128*100 = 12800.
It is: 2 to the power of 7 = 128
2 to the 7th power equals 128....
8
27 equals 128
256/2 = 128 for n.
2 to the power of 1 (21) equals 2.
find x when, 2x=128 2x=128 /2 /2 x=128 /2 x=64 then check your answer by doing the following if x=64, then what is 2x? 2(64)=? or 2 * 64=? or 2 x 64=? 2 times 64 equals 128!
(128)2 = 16,384
2^7 = 2x2x2x2x2x2x2 = 4x4x4x2 = 16x8 = 128
14 to the power of 2 means 14 x 14 which equals 196.
0.25
16 times 16 divided by 2 = 128