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Six times a number minus five is less than twice the number plus ten. 6 * n - 5 < 2 * n + 10 6n - 5 < 2n + 10 4n - 5 < 10 4n < 15 n < 15/4 This statement will hold true for all n < 15/4
So this statement is an equation whose left side contains the sum of (5) and (twice g), and the right side contains only 23. 2g + 5 = 23
111-11=100.. This way, you used the number 1 five times and reached the value of a 100.
If the number is N then 2N - 5 = 7 then 2N = 12 so that N = 6
Let the number be x and so if 2x+5 = -55 then the value of x is -30