given: 4w+(6k-3w)+(2-k)remove parentheses: 4w+6k-3w+2-kcollect like terms: 4w-3w+6k-k+2simplify: w+5k+2
you do 2 sets of parenthesis and check it. for example: w2(w squared)-7w-8 (w+1) (w-8) *if you add 1w and -8w you will get -7w, which is what they want you to get. and w & w multiply to get w2(w squared), which is also what the factoring wants. another example: 3w2 (3w squared)+2-8 (3w-4) (w+2) *same thing applies with 3w x w = 3w2, and -4 +2=2, which is the answer. use this theory in all of them, unless there is a greatest common factor (GCF).
Let's denote the width of the rectangle as ( w ) and the length as ( 3w ). The perimeter of a rectangle is given by the formula ( P = 2l + 2w ), where ( l ) is the length and ( w ) is the width. Given that the perimeter is 64 cm, we can write the equation ( 64 = 2(3w) + 2w ). Solving this equation, we find that the width is 8 cm and the length is 24 cm.
If l is the length and w is the width, we get the following two equations: l=3w-4 AND 2l+2w=64. Plugging l from the first equation into the second equation and solving for w, we get: 2*(3w-4) + 2w=64 8w-8=64 8w=72 w=9 Using w=9 and the first equation to find l, we get: l=3*9-4=23.
Perimeter of a rectangle is 2 times (length + width) P = 2 (L+W) In this case the length is 2m more than twice the width. That is written L = 2 + 2W P = 2 (L + W) 58 = 2 (2+ 2W + W) 58 = 2 (2 + 3W) 58/2 = (2(2+3W))/2 29 = 2 + 3W 29 - 2 = 2 + 3W - 2 27 = 3W 9 = W L = 2 + 2W L = 2 +2(9) L = 2 + 18 L = 20 For a rectangle with a perimeter of 58 m and a length that is 2 m more than twice the width, the length is 20 m and the width is 9 m.
3w^2, because your multiplying 3w by 1w so you get 3w to the second power
If you mean: 3w2-26w+16 then it is (3w-2)(w-8) when factored
Type this: ((w^2)/(w-6))((w^2-4w-12)/(w^2-3w) Into wolframalpha.com. It will give you the answer (too much for this box).
Expressed as an algebraic equation, this would equal 3w.
If: 3w = 42 Then: w = 14
3w -6 = -15 3w = -15+6 3w = -9 w = -3
3w^2 - 8w + 4 = (3w -2) (w-2) So 3w-2=0, then 3w=2, so w=2/3, w-2=0, so w=2. Your solutions are w=2/3 and w=2.
(3w(3w)/3w) + 5
The roots (or solutions) are the numbers that 'w' must be in order to make the equation true.Since the highest power of 'w' in the equation is the first power, there's only one solution.3w - 14 - 6 = 21Combine the -14 and the -6 on the left side:3w - 20 = 21Add 20 to each side:3w = 41Divide each side by 3 :w = 41/3 = 132/3
w2-3w = 0 w(w-3) = 0 w = 3 or w = 0
If: 3w-17 = 4 Then: w = 7
3w