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w2/(3w)2 = w2/9w2 = w2-2/9 = w0/9 = 1/9

or

w2/3w2 = 1/3

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Q: What is w to the second power divided by 3w to the second power?
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What is the length of a rectangle whose perimeter is 64cm if the length is 3 times the width?

24 cm Well, perimeter is L+W times 2. 2(L+W)=P If P is 64 and L is 3W, then: 64=2(3W+W)=2(4W)=8W 8W=64 W=8 L=3W L=3(8)=24


What is 4w plus 6k - 3w plus 2 - k?

given: 4w+(6k-3w)+(2-k)remove parentheses: 4w+6k-3w+2-kcollect like terms: 4w-3w+6k-k+2simplify: w+5k+2


How do you factor trinomials?

you do 2 sets of parenthesis and check it. for example: w2(w squared)-7w-8 (w+1) (w-8) *if you add 1w and -8w you will get -7w, which is what they want you to get. and w & w multiply to get w2(w squared), which is also what the factoring wants. another example: 3w2 (3w squared)+2-8 (3w-4) (w+2) *same thing applies with 3w x w = 3w2, and -4 +2=2, which is the answer. use this theory in all of them, unless there is a greatest common factor (GCF).


The length of a rectangle is 4 cm less than 3 times the width The perimeter is 64cm Find the width and length?

If l is the length and w is the width, we get the following two equations: l=3w-4 AND 2l+2w=64. Plugging l from the first equation into the second equation and solving for w, we get: 2*(3w-4) + 2w=64 8w-8=64 8w=72 w=9 Using w=9 and the first equation to find l, we get: l=3*9-4=23.


How do you get the answer to the math problem The perimeter of a rectangle is 58m and the length is 2m more than twice the width find the dimension for the length and the width?

Perimeter of a rectangle is 2 times (length + width) P = 2 (L+W) In this case the length is 2m more than twice the width. That is written L = 2 + 2W P = 2 (L + W) 58 = 2 (2+ 2W + W) 58 = 2 (2 + 3W) 58/2 = (2(2+3W))/2 29 = 2 + 3W 29 - 2 = 2 + 3W - 2 27 = 3W 9 = W L = 2 + 2W L = 2 +2(9) L = 2 + 18 L = 20 For a rectangle with a perimeter of 58 m and a length that is 2 m more than twice the width, the length is 20 m and the width is 9 m.