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Saying Log2x = 7 is another way of saying that 72 = x. So x = 49.

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Q: What is x if log 2x 7?
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What is x in the equation 12 to the 2x power equals 28?

(12)2x = 28(2x) log(12) = log(28)2x = log(28) / log(12) = 1.34098 (rounded)x = 0.67049 (rounded)


How do you sole X when logx-3 plus logx-2 equals log2x plus 24?

We can't see the parentheses, and there are at least two ways to read this.Here are solutions for the most likely two:--------------------------------------------------------log(x) - 3 + log(x) - 2 = log(2x) + 24Add 5 to each side:log(x) + log(x) = log(2x) + 29Subtract log(2x) from each side:log(x) + log(x) - log(2x) = 29Combine the logs on the left side, and massage:log( x2/2x ) = log( x/2 ) = 29Take the antilog of each side:x/2 = 1029Multiply each side by 2:x = 2 x 1029------------------------------------------------log(x - 3) + log(x - 2) = log(2x + 24)Combine logs on the left side:log[ (x-3) (x-2) ] = log(2x + 24)Take antilog of each side:(x-3) (x-2) = 2x + 24Expand the left side:x2 - 5x +6 = 2x + 24Subtract (2x+24) from each side:x2 - 7x - 18 = 0Factor:(x - 9) (x + 2) = 0Whence:x = 9x = -2We have to discard the solution [ x = -2 ] because one term in the equationis log(x-2).If 'x' were -2 then we'd have log(-4) but negative numbers don't have logs.


What is 7 plus x equals 2x?

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How do you solve 3 to the power of negative 2x plus 2 equals 81?

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What is the vertical asymptote of X minus 7 divided by negative 2X plus 7 times 2X plus 5?

f(x)= (x-7) /(-2x+7)(2x+5) set -2x+7=0 -2x=-7 x=7/2 set 2x+5=0 2x=-5 x=-5/2 x=7/2 and x=-5/2 are vertical asymptotes.


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2x = 17 then x = 8.5 2x+1=7 then x = 3 2x - 1 = 7 then x = 4 which is your problem


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-7 +2x = x + 8 2x - x = 7 + 8 x = 15


What is x when f of x equals -7 and f of x is defined to be 2x plus 8?

f(x) = 2x + 8 f(x) = -7 → 2x + 8 = -7 → 2x = -15 → x = -7½ = -7.5


What s the G of x if it equals log 2 x plus 2?

G(x) = log(2x) + 2, obviously!


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4x - 7 = 2x + 5 2x - 7 = 5 2x = 12 x = 6.