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Saying Log2x = 7 is another way of saying that 72 = x. So x = 49.
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∙ 12y ago
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What is the answer for 2x 1 7?
2x = 17 then x = 8.5 2x+1=7 then x = 3 2x - 1 = 7 then x = 4 which is your problem
Solve for X 6x-8 plus 2x-5 equals 7-2x?
6x-8+2x-5 = 7-2x 6x+2x+2x = 7+8+5 10x = 20 x = 20/10 x = 2
How do you solve 2logx plus 3logx equals 10?
2 log(x) + 3 log(x) = 105 log(x) = 10log(x) = 10/5 = 210log(x) = (10)2x = 100
How do you factor 2x squared minus 5x minus 7 equals 0?
(2x - 7)(x + 1)
If 4X - 7 equals 2X plus 5 what is the value of x?
(The original question was misphrased.) 4x-7 = 2x+5 resolves as 2x-7 = 5 2x = 12 x = 6
What is x in the equation 12 to the 2x power equals 28?
(12)2x = 28(2x) log(12) = log(28)2x = log(28) / log(12) = 1.34098 (rounded)x = 0.67049 (rounded)
How do you sole X when logx-3 plus logx-2 equals log2x plus 24?
We can't see the parentheses, and there are at least two ways to read this.Here are solutions for the most likely two:--------------------------------------------------------log(x) - 3 + log(x) - 2 = log(2x) + 24Add 5 to each side:log(x) + log(x) = log(2x) + 29Subtract log(2x) from each side:log(x) + log(x) - log(2x) = 29Combine the logs on the left side, and massage:log( x2/2x ) = log( x/2 ) = 29Take the antilog of each side:x/2 = 1029Multiply each side by 2:x = 2 x 1029------------------------------------------------log(x - 3) + log(x - 2) = log(2x + 24)Combine logs on the left side:log[ (x-3) (x-2) ] = log(2x + 24)Take antilog of each side:(x-3) (x-2) = 2x + 24Expand the left side:x2 - 5x +6 = 2x + 24Subtract (2x+24) from each side:x2 - 7x - 18 = 0Factor:(x - 9) (x + 2) = 0Whence:x = 9x = -2We have to discard the solution [ x = -2 ] because one term in the equationis log(x-2).If 'x' were -2 then we'd have log(-4) but negative numbers don't have logs.
What is 7 plus x equals 2x?
x+7 = 2x 2x = x+7 2x-x = 7 x = 7
How do you solve 3 to the power of negative 2x plus 2 equals 81?
3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1
What is the vertical asymptote of X minus 7 divided by negative 2X plus 7 times 2X plus 5?
f(x)= (x-7) /(-2x+7)(2x+5) set -2x+7=0 -2x=-7 x=7/2 set 2x+5=0 2x=-5 x=-5/2 x=7/2 and x=-5/2 are vertical asymptotes.
What is the answer for 2x 1 7?
2x = 17 then x = 8.5 2x+1=7 then x = 3 2x - 1 = 7 then x = 4 which is your problem
What is -7 plus 2x equals x plus 8?
-7 +2x = x + 8 2x - x = 7 + 8 x = 15
What is x when f of x equals -7 and f of x is defined to be 2x plus 8?
f(x) = 2x + 8 f(x) = -7 → 2x + 8 = -7 → 2x = -15 → x = -7½ = -7.5
What s the G of x if it equals log 2 x plus 2?
G(x) = log(2x) + 2, obviously!
What does the x equal in the problem 2x equals x plus 7?
It equals 7 since 2x = 7+x where 2 has 2x but 7 is one x because there is only one x . So it is 7.
How do you solve 2X plus 5 squared equals 7?
2x + 52 = 7 2x + 25 = 7 2x = 7 - 25 2x = -18 x = -18/2 x = -9
If 4x minus 7 equals 2x plus 5 what is x?
4x - 7 = 2x + 5 2x - 7 = 5 2x = 12 x = 6.
