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Well, darling, when you divide x to the power of 8 by x squared, you subtract the exponents. So, x to the power of 8 divided by x squared is x to the power of 8 minus 2, which simplifies to x to the power of 6. So, there you have it, x to the power of 6 is the sassy answer you're looking for.
What else can I help you with?
What is x to the fifth power divided by x to the third?
x squared
Simplify fully x squared minus 4x divided by x squared minus 6x plus 8?
x^2-4x/x^2-6x+8 = x(x-4)/(x-2)(x-4) = x/(x-2)
What is x squared multiplied by x squared?
(X2) (X2) = X4 x squared multiplied by x squared is x raised to the 4th power.
What is X cubed divided by X?
X2 (X squared)
Which expression is equivalent to 64-x squared?
(x-8)(x+8)
Simplify x to the power 8 divided by x squared?
x^8 / x^2 = x^6 You will notice it is just a matter of subtracting exponents.
What is x to the fifth power divided by x to the third?
x squared
What is 6 plus the result of x squared plus 2 divided by 1?
8 + X SQUARED
7x squared plus x minus 8 divided by x minus 1?
7x + 8
X squared minus 6x minus 16 divided by x plus 2?
x-8
What is x to the power of 8 divided by x?
x7
What is the two formulas for getting power?
In general:Power = energy transfer divided by timeIn electric circuits:Power = current x voltage x power factorPower = current squared x resitancePower = voltage squared / resistance
What is Sin squared x - Cos squared x divided by 1 - Tan squared x equals cos squared x?
22
Simplify fully x squared minus 4x divided by x squared minus 6x plus 8?
x^2-4x/x^2-6x+8 = x(x-4)/(x-2)(x-4) = x/(x-2)
What is 8 to the second power?
That would be 8 squared by the way. And the answer is 64
What is x squared divided by x?
x2 divided by x would simply be x.
What is 3X divided by X squared?
The expression 3X divided by X squared can be simplified by dividing the coefficient of X by the coefficient of X squared. In this case, 3X divided by X squared simplifies to 3/X. This is because when dividing by a term with an exponent, you subtract the exponents in the denominator from the exponents in the numerator.
