A fifth degree polynomial.
The idea is to write the factors as follows: (x + ...) (x + ...) (since all terms are positive in this case), then look for numbers that, when added, give 7, and when multiplied, give 10. Possible factor combinations of 10 are 1x10, and 2x5. The only pair of factors that works (that adds up to 7) is 2 and 5.
I assume that the question means 4x-7=2x+5. In that case, the answer x would equal 6.
You multiply the bases, for example, 23 x 53 = 103.The general rule is for real numbers ( but it works for others as well) a and b(ab)n =an bnI think it helps to see why this is true. Look at the example given23 is 2x2x253 is 5x5x5If we multiply these we have2x2x2x5x5x5 which is three 2's and three 5's.Now rearrange them which we can do because of the commutative property ofmultiplication and pair up each 2 with a 5 and here is what you have:(2x5)(2x5)(2x5)this is (2x5)3
its one million
Yah, (80 + 10)... it's a polynomial but after you add them up, (90) it's a monomial. Hope I helped :)
it is 3. You are doing APEX right?
2x1 is 2 2x2 is 4 2x3 is 6 2x4 is 8 2x5 is 10 2x6 is 12
Answer thi What is the coefficient of the term of degree 4 in this polynomial?2x5 + 3x4 - x3 + x2 - 12A. 1 B. 2 C. 3 D. 4 s question…
2, 4, 4.5 and 17
Two possibilities 1. (9+2) X 5 = 11 X 5 = 55 2. 9 + 2X5 = 9 + 10 = 19 Does your problem have parenthesis aka "()" symbols in it? ?