STEP 1-First do prime factorization of 3610 STEP 2-Make pairs for each (2 numbers of the same value)
STEP 3-The digit which is left alone is the least number to be multiplied by 3601 to make it a perfect square.
The answer is 230.
Oh, dude, to make 3000 a perfect square, you'd need to add the square of the nearest whole number to its square root, which is 55. So, the least number you'd have to add is 55 squared, which is 3025. But hey, who's counting, right?
5
Yes.... look at the number 20. It's a composite and it does have a square root.
The least common multiple is the least factor that can be common in every number. In algebra , L.C.M of 19, 7 and 4 is 19 *7* 4 =532. 532 is the least common multiple of 19 7 and 4.
It is 2 times 18 = 36 which is a perfect square number because 6 time 6 = 36
You need to factor it, into prime factors. Then, for every prime factor that appears an ODD number of times, you need to multiply 2306 by this prime factor. Multiply all such prime factors together to get your answer.
5607 + 18 = 5625, a perfect square. The perfect square of a square root is the number you started with.
The least one-digit number that is a perfect square is 0, as (0^2 = 0). However, if we consider only positive one-digit numbers, then the least perfect square is 1, since (1^2 = 1).
To determine the least number that 5202 must be multiplied by to become a perfect square, we first need its prime factorization. The prime factorization of 5202 is (2 \times 3 \times 7 \times 37). For a number to be a perfect square, all primes in its factorization must have even exponents. Here, each prime has an exponent of 1, so we need to multiply by each prime factor once more: (2 \times 3 \times 7 \times 37 = 5202). Therefore, the least number to multiply 5202 by is 5202.
1024
1024
Any such number has a perfect square factor.If you want examples, just multiply some prime factors together, making sure that at least one is repeated.
To determine the least number that must be multiplied to 21168 to make it a perfect square, we first find its prime factorization: (21168 = 2^4 \times 3^1 \times 11^1). For a number to be a perfect square, all the exponents in its prime factorization must be even. Here, the exponent of 3 and 11 are odd, so we need at least one more factor of each. Thus, we multiply by (3^1 \times 11^1 = 33). Therefore, the least number that must be multiplied to 21168 to make it a perfect square is 33.
1, 7, 11, 77, 121, 847 are the factors of 847.. or 847 = 11*77 ..inorder to make it a perfect square ..u need to multiply 7,11 to the existing number as 11 ,7 are prime numbers. so the least number will be 11*77*11*7
The least number is -6710. That gives the sum as 6710 + (-6710) = 0, which is a perfect square.The least positive number is 14.
It is: 7 because 7*112 = 784 which is a square number