x + y = 3
x * y = 4
Step 1: Put equation 1 into y = mx+b form
y = 3-x
Step 2: Substitute for y in the second equation
x*(3-x) = 4
Step 3: Multiply out
3x - x2 = 4
Step 4: Get the equation into quadratic form
-x2 + 3x - 4
x2 -3x + 4
Step 5: Plug into quadratic formula
x = (-(-3) +/- √(-3)2-4(1)(4))/ 2
x = (3 +/- √-7)/2
= (3+ i√7)/2 and (3- i√7)/2
There is no real number solutions for two numbers which multiply to 4 and add to 3 because i is present.
(1/2)(3 - i root(7)), and (1/2)(3 + i root(7))
Nothing in the reals
7
-31
-40
-11
19
-3
4
4 1
-13
4
3*4=12 3+4=7 hope this helps
-56