Q: What number divided by 10 has a remainder 9 divided by 9 has a remainder 8 divided by 8 has a remainder 7 divided by 7 has a remainder 6?

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6.8889

work backwards 0.1 * 10 = 1 1/10 = 0.1 1 divided by 10 equals 0.1

6

The lowest number is 393. Here's how - the lowest number divided by 11, R8 is 19. In order to maintain this remainder, the possible numbers must increase by 11 (30,41,52,etc). However, to be divisible by 5 with a R3, the number must end in a 3 or 8. So 63 is the first number that would match your first and last criteria. And to maintain that relationship, that sequence must increase by 55 each time (11x5). At 63 divided by 9, there is no remainder. Each time you add 55 to your sequence, and divide by 9, you would be increasing your remainder by 1 because 6x9=54, 55-54=1. Therefore, in order to get a remainer of 6 when divided by 9, you'll have to add six 55's to 63. 63 + (55x6) = 393 From that point, every time you add 495, you'll match the criteria. So 393+495=888, that works. 888+495=1383, that works. etc. Why 495? Because that is the product of your divisors - 5x9x11=495.

29.4118

Related questions

A number leaves reminder 6 when divided by 10. What is the remainder when the number is divided by 5? Justify your reasoning.

0.6667

37

Any number that can be divided by 2 and leave no remainder - for example, 2, 4, 6, 8, 10, is an even number.

37 is the number.

179 works until divided by 7 the remainder is 6. 2519 works till 10....

209

6.3

23.6

11.5

57

0.6