Starting with the zero, you add numbers sequentially. So, you add 1, then 2, then 3 then 4 etc.
t(n) = 3(n-1) + 1, for n = 1, 2, 3, etc
10 to the power 0 is 1
110 million = (1 x 10^8) + (1 x 10^7) + (0 x 10^6) + (0 x 10^5) + (0 x 10^4) + (0 x 10^3) + (0 x 10^2) + (0 x 10^1) + (0 x 10^0)
100.100 = (1 x 100) + (0 x 10) + (0 x 1) + (1/10) + (0/100) + (0/1000)
18,801,310 = (1 x 10^9) + (8 x 10^8) + (0 x 10^7) + (8 x 10^6) + (0 x 10^5) + (1 x 10^4) + (0 x 10^3) + (3 x 10^2) + (1 x 10^1) + (0 x 10^0)
3 is the answer
Not sure what PEMBAS is. It does not include D nd so division is clearly not part of whatever rule you are referring to. 50*1 - 60 - 60*0 + 10 = 50 - 60 - 0 + 10 = 0
The pattern rule for the given sequence is: starting with 0, add 3, then subtract 1, then add 2, then add 2, then add 3, then add 1, and the pattern repeats. This can be written as: +3, -1, +2, +2, +3, +1. This rule can be used to predict the next numbers in the sequence.
It seems there is a typo in your function rule. If you meant ( f(x) = 10 + 4x ), then the points on the graph can be determined by substituting different x-values. For example, if ( x = 0 ), then ( f(0) = 10 ) (point (0, 10)). If ( x = 1 ), then ( f(1) = 14 ) (point (1, 14)). Other points can be calculated similarly.
t(n) = 3(n-1) + 1, for n = 1, 2, 3, etc
The rule is 5, 10, 15 and so the next number will be 20+31 = 51
[(4 * 10^2) + (0 * 10^1) + (0 * 10^0)] + [(1 * 10^1) + (0 * 10^0)]
Oh, what a lovely little pattern we have here! It looks like we're adding 3, then adding 1, then adding 2, then adding 3 again. So, the pattern rule is to add 3, then 1, then 2, then 3, and so on. Keep exploring patterns and let your creativity flow!
The rule for the nth term is t(0) = 23 t(n) = mod[t(n-1) + 2n-1, 26] for n = 1, 2, 3, ...
0 1 0 1 0 1 0 10 1 0 1 0 1 0 1 0 10 1 01 this kind
Well, isn't that a lovely pattern you've got there! If we look closely, we can see that each number is decreasing by 10. So, the pattern rule for this sequence is to subtract 10 from the previous number to get the next one. Keep exploring patterns, my friend, and let your creativity flow!
.....0 10 | 0 01 | 0 1.....0 10 | 0 11 | 1 10 | 11 | 0