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Y = 2/3X - 3

you know Y, 0 out Y to find X intercept

2/3X - 3 = 0

2/3X = 3

X = 9/2

a line between Y = -3 and X = 9/2

comes from the 3rd quadrant, through the 4th quadrant and into the first

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Q: What should a graph with a y-intercept of negative 3 and a slope of 2 over 3 look like?
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