Let the integers be n-2 , n & n + 2
Hence
(n - 2) + n + (n+2) = 261Removing the brackets we have
n - 2 + n + n + 2 = 261
The '2' on the left hand sidfe adds to zero.
Hence
3n = 261
Divide both sides by '3'
n = 261/3 = 87
Hence n- 2 = 85
n + 2 = 89
So the three odd integers are
85,87,& 89.
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Divide the sum of the three consecutive odd integers by 3: 225/3 = 75. The smallest of these integers will be two less than 75 and the largest will be two more than 75, so the three consecutive odd integers will be 73, 75, and 77.
Those three odd integers are 43, 45, and 47.
Divide the sum of the three consecutive odd integers by 3: 402/3 = 134. The smallest of these integers will be two less than 134 and the largest will be two more than 134, so the three consecutive odd integers will be 132, 134, and 136.
Divide the sum of the three consecutive odd integers by 3: 51 / 3 = 17. The smallest of these integers will be two less than 17 and the largest will be two more than 17, so the three consecutive odd integers will be 15, 17, and 19.
The integers are 11, 13 and 15.