(Solving with algebra)
Lets call the two numbers x and y.
We want to find x and y so that x + y = 15 and xy = 36.
First, solve one equation for x or y. Here we will solve the first equation for x:
x = 15 - y
Because we know that 15 - y = x, we can plug it into the second equation:
(15 - y)(y) = 36.
Solving the above equation will give us one of the numbers:
Distribute: y^2 - 15y + 36 = 0
Factor: (x - 12)(x - 3) = 0
We can see here that the numbers are 12 and 3 (by solving for x).
The numbers in this problem are simple enough that you can use guess and check.
Start at a number (1, for example), and find the other number that would add to 15. If the numbers multiply to 36, then you found the two numbers. If not, try another one.
The two numbers are 12 and 3.
43
16 and -3 are the numbers which gives -48 when multiplied and 13 when added
21 and 7
Three eights are equal to a value of twenty four when added together. When they are multiplied eight to the third power is equal to 512.
There are no "two consecutive integers" that can do that.But there are two consecutive even integers that can: 8 and 10 .
An integer
26
A two digit number whose two digits added together equal 42 and multiplied together equal 82
Two (or four) digits added together cannot equal 42. Two-digit numbers multiplied together cannot equal 82.
Urny ony
How about 39*10 = 390 as one example
-8 and -8
-3 and 6
15 and -3
-4 and -25
95
-141