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We can rearrange this to the reverse operation, which should yield 96x + 1 = 289.
Subtract 1:
288 = 96x
Divide by 96:
288/96 = 3 = x
x = 3, which should be the answer.
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When 289 is divided by x the quotient equals 96 remainder 1. solve for x?
289/3 = 96 remainder 1 Therefore, x = 3.
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Minus 96 divided by minus 2?
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Three consecutive integers that have the sum of 96?
If three consecutive integers have the sum of 96, then the problem can be expressed with the equation... N + (N+1) + (N+2) = 96 ...Simplify that and solve and you get... 3N + 3 = 96 3N = 93 N = 31 ... so the three integers are 31, 32, and 33.
Related questions
When 289 is divided by x the quotient is 96 R1 Solve for x?
x = 3.
When 289 is divided by x the quotient equals 96 remainder 1. solve for x?
289/3 = 96 remainder 1 Therefore, x = 3.
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When 289 divided by x is 96 remainder 1 what is x?
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How many times can 3 go into 289?
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