Suppose the length of a side in the original square was S feet, so that the original area was S2 square feet.
The incresed side is (S+4) feet [not feets!] giving a new area of (s+4)2 sq feet.
So (S+4)2 = S2 + 64
S2 + 8x + 16 = S2 + 64
8S = 48
and so S = 6 ft
Area is proportional to the square of the linear dimensions. If the linear dimensions are doubled, the area is increased by a factor of 22 = 4. The new area is 9 x 4 = 36 square inches.
That is because a cube has 3 dimensions, and a square has 2.That is because a cube has 3 dimensions, and a square has 2.That is because a cube has 3 dimensions, and a square has 2.That is because a cube has 3 dimensions, and a square has 2.
The dimensions of a square with an area 36 square inches are:Side lengths: Six inchesPerimeter: 24 inchesDiagonal measurement: 8.485 inches
the length of a side of a square is the square root of the area of the square.
The square root of 144 is 12.12 x 12 = 144 so the dimensions would be 12cm by 12cm
Designate the side length of the original square by s. Then, from the problem statement, (s + 3)2 = 39 + s2. Multiplying out the binomial and collecting like terms yields 6s = 30 or s = 5.
Area is proportional to the square of the linear dimensions. If the linear dimensions are doubled, the area is increased by a factor of 22 = 4. The new area is 9 x 4 = 36 square inches.
Any one dimension increased by 2, or any two dimensions increased by the square root of 2 orall three dimensions increased by the cube root of 2.
Any one dimension increased by 3, or any two dimensions increased by the square root of 3 or all three dimensions increased by the cube root of 3.
The area of a rug does not provide enough information to determine its dimensions. For a start, it is not even possible to determine the shape of the rug: circular, oval, square, rectangular or some other shape.
9 feet was the original side lengths
The original square was 6 ft along each side. Let s be the side of the original square, then: Area_square = s x s = s2 Area_new_square = (s + 4) x (s + 4) = s2 + 8s + 16 But: Area_new_square = Area_square + 64 => s2 + 8s + 16 = s2 + 64 => 8s = 48 => s = 6
To get the original number, multiply the square root of the number by itself.
The area of a triangle does not provide enough information to determine its dimensions.
The dimensions are: The dimensions of the square are LW Length x width (srry about the last one)
Area increase as the square of linear dimensions. So area is 9times means linear dimension increased to sqrt(9) = 3 times their original. ie r = 3
The dimensions of square feet is Length2 or L2