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How do you use the y intercept and slope of a line to graph it?
Here is an example. y = 2x + 3; that is, the slope is 2, and the y-intercept is 3. Start with the y-intercept. Plot the point (0, 2). Now, for the slope: a slope of 2 means that every time you go 1 to the right, you have to go 2 up. Thus, the next point to the right (if you use plotting paper, and one square for each number) would be 1, 4. That is, if you add 1 to the x-coordinate, you have to add 2 to the y-coordinate. After that, once again adding 1 and 2, you get 2, 6. Plot these points, and draw a line through them. Similarly, if you go to the left, for every unit you go to the left you have to go 2 units down. 2, in this case, is the slope; for other slopes, you just have to change the numbers.
How do you draw the graph of y = -3x + 4?
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How do you construct 32 degree angle using ruler and compass?
Well, honey, you start by drawing a line with your ruler. Then, you put the point of your compass on one end of the line and draw an arc. Next, you put the point of your compass on where the arc intersects the line and draw another arc. Where those arcs meet is your 32-degree angle. Voila!
Is y equals 2 to the x power a linear equation?
If you mean y = 2^x, then no, it is not a linear equation. This is an exponential equation. The graph of this exponential equation would start out near zero on the left-hand side (there is a horizontal asymptote at y = 0) and would gradually increase as you move to the right: overall, it has a curved shaped. If you mean y = 2x, then yes, it is a linear equation.
Rectangular coordinate system?
x, y, and z ordinates from origin 0, x and y are two dimensional ordinates ie graph axis, z adds third dimension. eg ordinates for point are say 10, 25, 15: start at 0, right for 10(x), left for 25(y), then vertically off the paper toward you for 15(z) both turns are right angles
