Creating an open top box
The inequality -6 > x+5 can be rewritten -11 > x (by subtracting five from each side) or rather x < -11. To graph this on a number line, draw an open circle over the number -11 (if the inequality included "or equal to" the circle would be filled in). Then draw a line/arrow coming out of the circle over the number line. The line should only be drawn over the portion of the number line that makes the inequality true. For instance, choose a test point. When x is -20, the inequality is true: -20 < -11. So in this case, the arrow coming out of the open circle will point to the left, in the direction that the number line is getting smaller.
5x > -20 divide both sides by 5; x > -4 On a number line graph all real numbers to the right of -4 and use an open dot at -4 to indicate that -4 is not a solution.
We assume you are graphing on a number line, not an x-y plane. Draw an "open" circle (not filled in) at -4, and a line from it across to the right end of the number line. Put an arrow on the end of the line to show that the graph continues to the right.
An open or closed circle are used to graph an inequality in one variable. An open circle is used if the value at the end point is excluded from the feasible region while a closed circle is used if the value at that point is within the accepted region.
6
Up and to the right
4
The question contains an expression, not an equation. An expression does not have a graph. Furthermore, even if it were an equation, its form suggests that it would be a linear equation and a linear equation does not open in any direction.
It is not possible to answer the question because there is no equation - only an expression.
Since 'x' and 'y' both appear to the first power, this is a linear equation.That means that the graph is a straight line, and it doesn't 'open'.The line has a slope of -1, and it cuts the y-axis at y=9.
VV2-4x+4y-4=0
A parabola can open left, down, right, or left on a graph, if that's what you mean:\
Neither statement is true. The graph of the absolute value of a function which is always non-negative will be the same as that of the original function and this need not open in any direction. Also, the graph of y = abs[x*(x-1)*(x+2)] is not symmetrical so there is no coefficient which will determine a line of symmetry.
None of the following sets would.
open dot means < or > but not equal to.
Left