Upwards.
To graph "y ≠ a" on a number line, first plot the point corresponding to "a." Then, use an open circle at "a" to indicate that this value is not included in the solution. Finally, shade the entire number line except for the point "a" to show that all other values are acceptable for "y."
To write a compound inequality from a graph, first identify the critical points where the graph changes direction or has boundaries. Determine the intervals represented by the shaded regions—if they are open or closed. Then, express the relationship between these intervals using "and" (for overlapping regions) or "or" (for separate regions) to form the compound inequality. Finally, use inequality symbols to represent the boundaries of each interval accurately.
Creating an open top box
The inequality -6 > x+5 can be rewritten -11 > x (by subtracting five from each side) or rather x < -11. To graph this on a number line, draw an open circle over the number -11 (if the inequality included "or equal to" the circle would be filled in). Then draw a line/arrow coming out of the circle over the number line. The line should only be drawn over the portion of the number line that makes the inequality true. For instance, choose a test point. When x is -20, the inequality is true: -20 < -11. So in this case, the arrow coming out of the open circle will point to the left, in the direction that the number line is getting smaller.
To determine the inequality graphed on a number line, you would need to identify the points marked on the line and the direction of any arrows or shading. If the line is shaded to the left of a point (for example, -2) with an open circle, it represents the inequality ( x < -2 ). If it’s shaded to the right with a closed circle, it would indicate ( x \geq -2 ). Please provide specific details about the graph for a more precise answer.
6
Up and to the right
4
The question contains an expression, not an equation. An expression does not have a graph. Furthermore, even if it were an equation, its form suggests that it would be a linear equation and a linear equation does not open in any direction.
It is not possible to answer the question because there is no equation - only an expression.
Since 'x' and 'y' both appear to the first power, this is a linear equation.That means that the graph is a straight line, and it doesn't 'open'.The line has a slope of -1, and it cuts the y-axis at y=9.
VV2-4x+4y-4=0
A parabola can open left, down, right, or left on a graph, if that's what you mean:\
When 'a' is positive in a quadratic function of the form (y = ax^2 + bx + c), the graph opens upwards. This means the vertex of the parabola is the lowest point on the graph, and as you move away from the vertex in either direction, the values of (y) increase.
Neither statement is true. The graph of the absolute value of a function which is always non-negative will be the same as that of the original function and this need not open in any direction. Also, the graph of y = abs[x*(x-1)*(x+2)] is not symmetrical so there is no coefficient which will determine a line of symmetry.
None of the following sets would.
open dot means < or > but not equal to.