Unfortunately, the browser used by Answers.com for posting questions is incapable of accepting mathematical symbols. This means that we cannot see the mathematically critical parts of the question. We are, therefore unable to determine what exactly the question is about and so cannot give a proper answer to your question. Please edit your question to include words for symbols and resubmit.
r+d/t
S = v*t s = displacement v = velocity t = time
t - 17 = 48 The first step is to move the -17 to the right side of the equation and end up with: t = 48 + 17. (When you switch sides, the sign changes) To solve the equation: t = 65
Do you mean f(t) = -16t^2 - 48t + 160? This is a function, which can't be "solved" as it is. - you could factor it: -16(t + 5)(t - 2) - you solve for f(t) = 0: t = 2, -5
using the t-table determine 3 solutions to this equation: y equals 2x
r+d/t
Yes and t = 1 in both equations
F(t) = $(0.45 x t + 33)
Well, let's break it down nice and easy. To solve the equation vf = vi + at, you first subtract vi from both sides to isolate vf. Then, you multiply a by t and add the result to vi to find vf. Remember, take your time and enjoy the process of solving equations like this - it's just like painting a happy little picture!
There is no equation in the question: only an expression.
S = v*t s = displacement v = velocity t = time
Which expression is equivalent to cot t sec t
If xwat are variables or constants that are multiplied together, divide each side of the equation by the non-"t" ones to arrive at a "t=" equation. For example, if the equation is xwat = 1, then t = 1/xwa. If there should have been + or - operations in the equation, reverse those first, before doing any multiplying or dividing. Perform the same operations on both sides of the equation. For example, if the equation were xw+at = 1, then at = 1 - xw, then t = (1-xw)/a.
The equation for the average over time T is integral 0 to T of I.dt
In a Solow model, a differential equation exists because the optimal growth rate is a difference between two functions, whose optimisation is their derivative set equal to zero. Consider:Break-even investment is equivalent to the minimal level to maintain the capital-labour ratio:(n + g + d)k(t)And actual investment is:sf(k(t))The differential solution to this equation describes the optimal outcome. Specifically, we optimise economic growth by choosing the savings versus consumption ratio such that the equationsf(k(t)) - (n + g + d)k(t)is optimised. This equation represents the derivative of the capital-labour ratio. Therefore, its optimisation is equivalent to0 = sf(k(t)) - (n + g + d)k(t)thussf(k(t)) = (n + g + d)k(t)when k(t) = f(k(t)), thens = n + g + d
There are three "T" symbols to be placed inside the initial "T" to make a valid Roman numeral equation. The solution would be: III = T.
Frequency (f) is the inverse of period (T), so the equation relating the two is: f = 1/T