(n + 6) - 5 which can be simplified to n + 1
Incidentally, the word is subtracted.
Find the sum of the first hundred even natural number divisible by 5?
5
5 5+4 = 9 52+42 = 41
To find 8 times the sum of a number and 5, you first need to calculate the sum of the number and 5. Let's say the number is represented by 'x'. So, the sum of the number and 5 would be x + 5. Then, you would multiply this sum by 8 to get the final result, which would be 8(x + 5) or 8x + 40.
the quotient of 12 and a number h
Once.
" 3x + 5 " does.
10 < x + 5 < 20
The algebraic expression for "4 less than the sum of a number and 5" is (n + 5) - 4, where n represents the unknown number.
3, 5, 7 and 9.
The sequence 0112358 represents the Fibonacci sequence, where each number is the sum of the two preceding ones. The next number in this sequence is 13, as it is the sum of the last two numbers, 5 and 8. Thus, the next number is 13.
The sum of 3 and a number, equaling 5, (if you want to know what the number is...) is 2 3+2=5
3*(5+x) or 3(5+x)
And the sum of 5..? Uhh... Is it 5?
The number is 45. The sum of its digits i.e. 4+5=9 Five times the sum of its digits i.e. 5 times 9 which is 45
0.8333
In Roman numerals, the symbol "V" represents the number 5.