(n + 6) - 5 which can be simplified to n + 1
Incidentally, the word is subtracted.
Find the sum of the first hundred even natural number divisible by 5?
5
5 5+4 = 9 52+42 = 41
To find 8 times the sum of a number and 5, you first need to calculate the sum of the number and 5. Let's say the number is represented by 'x'. So, the sum of the number and 5 would be x + 5. Then, you would multiply this sum by 8 to get the final result, which would be 8(x + 5) or 8x + 40.
the quotient of 12 and a number h
Once.
" 3x + 5 " does.
10 < x + 5 < 20
The algebraic expression for "4 less than the sum of a number and 5" is (n + 5) - 4, where n represents the unknown number.
The algebraic expression for the sum of 6 times a number and 5 can be written as ( 6x + 5 ), where ( x ) represents the unknown number. This expression indicates that you first multiply the number by 6 and then add 5 to that product.
3, 5, 7 and 9.
When one number is added to another number, the result is called the sum. The sum represents the total quantity obtained from the addition of the two numbers. For example, if you add 3 and 5, the sum is 8.
The sequence 0112358 represents the Fibonacci sequence, where each number is the sum of the two preceding ones. The next number in this sequence is 13, as it is the sum of the last two numbers, 5 and 8. Thus, the next number is 13.
The product of five and the sum of a number and six can be expressed mathematically as ( 5 \times (x + 6) ), where ( x ) represents the number. This means you first add the number ( x ) to six and then multiply the result by five.
The sum of 3 and a number, equaling 5, (if you want to know what the number is...) is 2 3+2=5
3*(5+x) or 3(5+x)
And the sum of 5..? Uhh... Is it 5?