Which value of c makes y2 8y c a perfect square trinomial?

Answer 1

To make the expression y^2 + 8y + c a perfect square trinomial, we need to find the value of c that completes the square. The formula to complete the square is (b/2)^2, where b is the coefficient of the y-term, which is 8 in this case. So, (8/2)^2 = 16. Therefore, the value of c that makes the trinomial a perfect square is 16.

Answer 2

I'm going to go out on a limb and assume that

y2 8y c

actually means

y^2 + 8y + c

c = 16 makes a perfect square:

(y + 4)^2

= (y+4)*(y+4)

= y^2 + 8y + 16