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Q: Why does the square root of 27 have to be between 5 and 6?

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The square root of 27 plus the square root of 5 = 7.4322204

Square root of 5 = ± 2.236068Square root of 11 = ± 3.316625

Try squaring different integers (hint: in this case, the integers will be fairly small). If you find that the square of one integer is less than 27, and the square of the next integer is more than 27, you have your answer.

square root(-5) = 2.23606798 i

b over the square root of 5 The square root of 5b squared is 5b, and the simplified form of the square root of 125 is 5 root 5. The 5s then cancel out leaving b over the square root of 5.

Related questions

The square root of 27 plus the square root of 5 = 7.4322204

Do you mean which 2 integers the square root of 27 falls between? If so, then the square root of 27 is 3*sqrt3, or about 5.2. So between 5 and 6.

182.25

-6 and -5, or 5 and 6.

The square root of 17 is between 4 and 5.

Since 27 is between 25 and 36, then √27 is between √25 and √36. So √27 is between 5 and 6, which are two consecutive numbers.

5 Square root 3. square root 27 = square root 9*3 = 3square root 3 3square root3 + 2square root3 = 5Square Root3 because both have a square root 3.

Every number is a square root of some number. So any number between 5 and 6 is a square root.

27.00

52 = 25 and 62 = 36 because 27 is between 25 and 36 then its sq root must be between 5 and 6

The square root is between 5 and 6.

27

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