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Since 5^2 is 25 and 6^2 is 36,

the square root of 27 must be in between 5 and 6,

This is because 27 is in between 25 and 36.

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Blabby Pancake

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βˆ™ 2021-08-15 22:35:48
This answer is:
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Adriana Doyle

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βˆ™ 2021-08-18 07:05:41
can you explain how you know that
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Elian Collins

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βˆ™ 2021-08-18 16:05:33
ty
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Algebra

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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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βˆ™ 2013-04-14 21:23:37

√25 = 5 and √36 = 6 ...

Since 27 is between 25 and 36, its Square Root must be between 5 and 6.

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Q: Why does the square root of 27 have to be between 5 and 6?
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What does the square root of 27 plus the square root of 5?

The square root of 27 plus the square root of 5 = 7.4322204


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Do you mean which 2 integers the square root of 27 falls between? If so, then the square root of 27 is 3*sqrt3, or about 5.2. So between 5 and 6.


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