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Why power waveform is not symmetrical to X-Axis in R-L circuit?
Wiki User
∙ 13y ago
- Because power dissipated in rl circuit is given by p= 1/2(Li²)+ i²R which will give a curve and not a linear graph. Secondly the graph is a cosine curve ,with a phase difference between current and voltage. Hence the waveform is not symmetrical to x-axis .
ANANYA SINGH
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This depends on the circuit in question. If the circuit only has resistors and maybe incandescent light bulbs, then with an equvalent RMS voltage of AC, to the previous DC, the circuit will behave almost the same. If the circuit has components such as capacitors and inductors, then the current will be shifted to flow at a waveform which no longer matches the voltage waveform. If you're talking about a circuit which was designed to run on a 12 volt battery, then you go and plug it into the wall, it will probably break, as the equivalent voltage causes a much higher current than these components were designed to handle.
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What type of waveform is produced by Ferroresonant power supply?
ferro-resonant power supply?
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