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Write the complex number 2 - i divided by 5 plus i in the usual a plus bi form?
Rayz17
7
Russell Herman
Wiki User
∙ 15y ago(2 - i)/(5 + i) = (2 - i)(5 - i)/(5 + i)(5 - i) = (10 - 2i - 5i + i^2)/(25 - i^2)
(substitute i^2 = -1)
= (10 - 7i - 1)/(25 - (-1))
= (9 - 7i)/26
= 9/26 - (7/26)i
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