The equation is -3x+2y=12
To find the y intercept, we simply let x equal 0.
So -3(0)+2y=12
or y=6, this is the y intercept.
The point is (0,6)
You can also write the original equation as
2y=3x+12 or y=3/2x +6 which tells you write away the
y intercept is 6 since this is slope intercept form (y=mx+b) where b is the slope.
Now to find the x intercept, let y=0
So you have 0=3/2x+6 or
-6=3/2x ro -12=3x and the x intercept is -4.
It is probably easier to set y=o in the original equation
so we have -3x+0=12 and x=-4 again so the point is (-4,0)
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x+2y = 2 2y = -x+2 y = -0.5x+1 Therefore the slope is -0.5 and the y intercept is 1
2y - 4x = -12 Algebraically rearrange to 2y = 4x - 12 Divide both sides by '2' y = 2x - 6 So at the 'y' intercept, x = 0 Substituting x = 0 We have y = 2(0) - 6 Anything multiplied '0' is equal; to '0' Hence y = 0 - 6 y = -6 is the value of the y-intercept.
If you mean: 2y = -4x-12 then y = -2x-6 and -6 is the y intercept
3x+2y-5=0 3x+2y=5 Im lost im only 12 work out the rest hope i helped
Put in this form.......Y = mX + bb = Y intercept.3X - 2Y = 6- 2Y = - 3X + 6Y = (3/2)X - 3================