0
What else can I help you with?
Codes for quadratic equation on vb net?
dim a as string dim b as string dim c as string a = val(txt1.text) b = val(txt2.text) c = val(txt3.text) lbl1.caption = (-b + sqr((b ^ 2) - ((4) * (a * c))) / (2 * a) lbl2.caption = (-b - sqr((b ^ 2) - ((4) * (a * c))) / (2 * a)
What is the definition of the transitive property of equality?
The transitive property of equality states for any real numbers a, b, and c: If a = b and b = c, then a = c. For example, 5 = 3 + 2. 3 + 2 = 1 + 4. So, 5 = 1 + 4. Another example: a = 3. 3 = b. So, a = b.
How do you write an equation for a parabola with a vertex at -4 2 and y-intercept -2?
1. The y-intercept of a parabola with equation y = ax^2 + bx + c is c. So, c = -22. The vertex is (x, y) = (-4, 2), where x = - b/2ax = - b/2a-4 = - b/2a(-4)(-2a) = (-b/2a)(-2a)8a = bSo we have:y = ax^2 + bx + c (substitute what you know: 2 for y, -4 for x, 8a for b, and -2 for c)2 = a(-4)^2 + (8a)(-4) + (-2)2 = 16a - 32a - 22 = - 16a - 2 (add 2 to both sides)4 = -16a (divide by -16 to both sides)-1/4 = aSince b = 8a, then b = 8(-1/4) = -2 Since a = -1/4, b = -2, and c = -2, then we can write the equation of the parabola asy = (-1/4)x^2 - 2x - 2.
10 p in g?
4 l on a c = 4 legs on a chair, 4 f on b b is 4 faces on big ben------- so what is 10 p in g
What are the five steps for solving quadratic equations?
the quadratic equation is this..-b+-sqrt(b2-4(a)(c)) / 2ayour equation has to have the form like this...ax2 + bx + cStep 1: Identify your a, b, and c and put them in the correct place in the quadratic equationStep 2: Solve the 4(a)(c) part... its just multiplicationStep 3: square the b and then minus 4(a)(c) from itStep 4: take the square root of the answer from step 3Step 5: take -b and add and subtract it from the answer from step 4 and then divide it by 2 times a. you should get two answers. you have to separately take -b plus the answer from step 3 and take -b minus the answer from step 3
Yyyy you r yyyyy you b i c you r y plus y 4?
That's usually translated as, "Too wise you are, too wise you be, I see you are too wise for me."
What is 4 C B?
What is 4 C B
If you have a 10 measuring cup 4 measuring cup and a 3 measuring cup how many pours does it take to get the 4 to 4 the 3 to 1 and the 10 to half?
Assuming the 10 = Cup A, 4 = Cup B and 3 = Cup C 1) Fill Cup C (A=0, B=0, C=3) 2) Pour Cup C into Cup A (A=3, B=0, C=0) 3) Fill Cup B (A=3, B=4, C=0) 4) Fill Cup C from Cup A (A=3, B=1, C=3) 5) Pour the remainder of Cup B into Cup A (A=4, B=0, C=3) 6) Empty Cup C (A=4, B=0, C=0) 7) Fill Cup B (A=4, B=4, C=0) 8) Fill Cup C from Cup A (A=4, B=1, C=3) 9) Pour the remainder of Cup B into Cup A (A=5, B=0, C=3) 10) Empty Cup C (A=5, B=0, C=0) 11) Fill Cup B (A=5, B=4, C=0) 12) Fill Cup C from Cup A (A=5, B=1, C=3) 13) Empty Cup C (A=5, B=1, C=0) 13) Pour the remainder of Cup B into Cup C (A=5, B=0, C=1) 14) Fill Cup B (A=5, B=4, C=1) so assuming you count the filling of cups as pours your answer is 14
Maria keeps her four stuffed bears lined up on a shelf over her bed how many arrangements of the bears are possible?
The answer is 4! (4 factorial), the same as 4x3x2x1, which equals 24 combinations. The answer is 24 and this is how: A b c d A b d c A c d b A c b d A d c b A d b c B c d a B c a d B d a c B d c a B a c d B a d c C d a b C d b a C a b d C a d b C b d a C b a d D a b c D a c b D b c a D b a c D c a b D c b a
What is proof of Heron's Formula?
This is a proof that uses the cosine rule and Pythagoras' theorem. As on any triangle with c being the opposite side of θ and a and b are the other sides: c^2=a^2+b^2-2abcosθ We can rearrange this for θ: θ=arccos[(a^2+b^2-c^2)/(2ab)] On a right-angle triangle cosθ=a/h. We can therefore construct a right-angle triangle with θ being one of the angles, the adjacent side being a^2+b^2-c^2 and the hypotenuse being 2ab. As the formula for the area of a triangle is also absinθ/2, when a and b being two sides and θ the angle between them, the opposite side of θ on the right-angle triangle we have constructed is 4A, with A being the area of the original triangle, as it is 2absinθ. Therefore, according to Pythagoras' theorem: (2ab)^2=(a^2+b^2-c^2)^2+(4A)^2 4a^2*b^2=(a^2+b^2-c^2)^2+16A^2 16A^2=4a^2*b^2-(a^2+b^2-c^2)^2 This is where it will start to get messy: 16A^2=4a^2*b^2-(a^2+b^2-c^2)(a^2+b^2-c^2) =4a^2*b^2-(a^4+a^2*b^2-a^2*c^2+a^2*b^2+b^4-b^2*c^2- a^2*c^2-b^2*c^2+c^4) =4a^2*b^2-(a^4+2a^2*b^2-2a^2*c^2+b^4-2b^2*c^2+c^4) =-a^4+2a^2*b^2+2a^2*c^2-b^4+2b^2*c^2-c^4 (Eq.1) We will now see: (a+b+c)(-a+b+c)(a-b+c)(a+b-c) =(-a^2+ab+ac-ab+b^2+bc-ac+bc+c^2)(a^2+ab-ac-ab-b^2+bc+ac+bc-c^2) =(-a^2+b^2+2bc+c^2)(a^2-b^2+2bc-c^2) =-a^4+a^2*b^2-2a^2*bc+a^2*c^2+a^2*b^2-b^4+2b^3*c-b^2*c^2+2a^2*bc-2b^3*c+(2bc)^2-2bc^3+a^2*c^2-b^2*c^2+2bc^3-c^4 =-a^4+2a^2*b^2+2a^2*c^2-b^4+(2bc)^2-c^4-2b^2*c^2 =-a^4+2a^2*b^2+2a^2*c^2-b^4+2b^2*c^2-c^4 (Eq.2) And now that we know that Eq.1=Eq.2, we can make Eq.1=(a+b+c)(-a+b+c)(a-b+c)(a+b-c) Therefore: 16A^2=(a+b+c)(-a+b+c)(a-b+c)(a+b-c) A^2=(a+b+c)(-a+b+c)(a-b+c)(a+b-c)/16 =[(a+b+c)/2][(-a+b+c)/2][(a-b+c)/2][(a+b-c)/2] And so if we let s=(a+b+c)/2 A^2=s(s-a)(s-b)(s-c)
If A is less than B and B plus C equals 10 and none of them equal zero then which of the following must be true?
Well, isn't that just a happy little math problem! If A is less than B and B plus C equals 10, then it must be true that A plus C is less than 10. Just remember, in the world of numbers, everything adds up beautifully in the end.
Notes to play you got to feeling?
here's the notes for i gotta feeling on the recorder by the black eyed peas: d' d' d' d' c' c' bb c'c'c'c' c'c'c'c' b b b b b b b b a ( 4 beats) g ( 4 beats) a ( 4 beats) g ( 4 beats) c' a ( 4 beats) g ( 4 beats) a ( 4 beats) g ( 4 beats) E A G C' B..........E E C' B A G E C' B ......... E E C' B A G E D' B E E D' B A G E D' D' B A G ... C' B E E C' B A G E C' B ......... E E C' B A G E D' B E E D' B A G E D' D' B A G ... C' B E E C' B A G E C' B ......... E E C' B A G E D' B E E D' B A G E D' D' B A G ... C' B E E C' B A G E C' B ......... E E C' B A G E D' B E E D' B A G E D' D' B A G ... C' B A...G. Thats the begining thnks ;)
the ratio of A to B is 2:3 and the ratio of B to C is 4:5. what is the ratio of A to C?
Oh, what a happy little problem we have here! To find the ratio of A to C, we can simply multiply the two ratios together. So, 2:3 times 4:5 gives us 8:15. That's the beautiful ratio of A to C, just like painting a lovely landscape with different colors blending harmoniously together.
How do you play i got to feeling on recorded?
Here's the notes for i gotta feeling on the recorder ( can also be played on the keyboard with the same notes) by the black eyed peas:d' d' d' d' c' c' bb c'c'c'c' c'c'c'c' b b b b b b b b c'c'c'c' c'c'c'c'a ( 4 beats) g ( 4 beats)a ( 4 beats) g ( 4 beats) c'a ( 4 beats) g ( 4 beats)a ( 4 beats) g ( 4 beats)E A G C' B..........E E C' B A G E C' B ......... E E C' B A G E D' B E E D' B A G E D' D' B A G ... C' BE E C' B A G E C' B ......... E E C' B A G E D' B E E D' B A G E D' D' B A G ... C' BE E C' B A G E C' B ......... E E C' B A G E D' B E E D' B A G E D' D' B A G ... C' BE E C' B A G E C' B ......... E E C' B A G E D' B E E D' B A G E D' D' B A G ... C' BA...G. Thats the begining thnks ;)
What are the notes to believe by polar express on viola?
PLEASE NOTE ~ |= MEASURE SEPARATION ALL OF THE Ds ARE HIGH D AND OPEN D WILL BE WRITTEN IN ITALICS ( D )4/4 B B B B B B| B D G A B| C# C# C# C# C# B B|B A A B D|B B B B B B| B D G A B| C# C# C# C# C# B B B| D D C# A G| D B A G D | D B A G E | E C# B A F | D D C# A B| D B A G D | D B A G E | E C# B A D D D D | E-(high) D C# A G D| B B B B B B| B D G A B| C# C# C# C# C# B B|B A A B D| B B B B B B| B D G A B| C# C# C# C# C# B B B| D D C# A G|
Associative addition math problem?
a+(b+c)=b+(a+c) 2+(7+4)=7+(2+4)
How do you solve a equals b minus 4 over c for b?
Well. Multiply both sides by 'c'. After that you should have something like ac=b-4 then you add 4, to get this result 4+ac=b.
