-1/2
60 * pi / 180
The tangent of 60 degrees is sqrt(3) = 1.732 approx. The shape or size of the triangle is irrelevant.The tangent of 60 degrees is sqrt(3) = 1.732 approx. The shape or size of the triangle is irrelevant.The tangent of 60 degrees is sqrt(3) = 1.732 approx. The shape or size of the triangle is irrelevant.The tangent of 60 degrees is sqrt(3) = 1.732 approx. The shape or size of the triangle is irrelevant.
60
Tan(60) = Sin(60)/ Cos(60) Sin(60) = sqrt(3)/2 Cos(60) = 1/2 Hence Sin(60) / Cos(60) = [sqrt(3) / 2] / [1/2} => sqrt(3) / 2 X 2/1 sqrt(3) Hence Tan(60) = sqrt(3) = Numerically = 1.732050808....
Co-60 is an isotope of Co-59, which is a common component of steel. You get Co-60 by irradiating it with neutrons, so you get Co-60 in nuclear reactors, or anywhere else you have a neutron flux.
0.602
The tangent of 60 degrees is equal to the square root of 3, or approximately 1.732. This value can be derived from the properties of a 30-60-90 triangle, where the ratio of the lengths of the sides opposite the angles gives the tangent. Specifically, in a 30-60-90 triangle, the side opposite the 60-degree angle is √3 times the length of the side opposite the 30-degree angle.
Atomic Mass or mass no
The half-life of cobalt-60 (Co-60) is approximately 5.27 years. This means that after this period, half of the original amount of Co-60 will have decayed into stable nickel-60. Co-60 is commonly used in radiation therapy and industrial applications due to its gamma radiation.
The "60" in Co-60 represents the atomic mass number of the cobalt isotope. It indicates that the cobalt nucleus contains 60 protons and neutrons combined.
Providing that the pole is on level ground you have the outline of a right angled triangle with an adjacent side of 92 ft (the shadow of the pole) and a opposite side of 60 ft (the height of the pole). To find the angle of elevation use the tangent ratio. Tangent = Opposite/Adjacent Tangent = 60/92 = 0.652173913 Tan-1(0.652173913) = 33.11134196 degrees Therefore the angle of elevation is 33o correct to two significant figures.
In the beta minus decay of cobalt-60 (Co-60), a neutron in the nucleus is transformed into a proton, resulting in the emission of a beta particle (electron) and an antineutrino. The balanced nuclear reaction can be represented as: [ ^{60}{27}\text{Co} \rightarrow ^{60}{28}\text{Ni} + e^- + \bar{\nu} ] Here, Co-60 decays into nickel-60 (Ni-60), with the emission of a beta particle (e^-) and an antineutrino (ν̄).