consider the poles as on the right hand side of s plane ie. (s-1) or (s-2)
Consider the simple case in which transfer function is 1/(s-2) ie.pole 2 in the RHP of s plane
if we take the inverse laplace transform we e^2t u(t)......
our output is Ae^2t u(t).....
immediately we can recognize that e^2t for t>0 is not converging ..as t->infinity the output also tends to infinity...
but for system with transfer functio 1/(s+2) the inverse is e^-2t and it is quite clear that it is a converging or bounded or stable
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