Let Q be all the rational numbers, where Q={m/n:m is an integer and n is a natural}
Every number does not belong to Q is irrational.
It is proven that between two irrational numbers there's an irrational number. There's no method, you just know you can find the number.
The answer to this question confuses me. The square root of two is an irrational number, so obviously if the square root of two is squared it becomes two which is a rational number. Thinking of it that way then the answer is yes, the square of an irrational number can be a rational number. But . . . You had to know beforehand that the irrational number was the square root of another number. If you start out with an irrational number such as Pi you cannot square it because you cannot know the entire number in order to square it.
Pi is an irrational number. Johann Heinrich Lambert proved that in the late 18th Century.
An irrational number.
It is always rational.
No. The sum of an irrational number and any other [real] number is irrational.
The sum of a rational and irrational number must be an irrational number.
rational * irrational = irrational.
No, 3.56 is not an irrational number. 3.56 is rational.
-Pi is irrational, because it does not terminate or repeat. Whenever you multiply an irrational number by a rational number (-1), the result is an irrational number.
A negative irrational number can be thought of as an irrational number multiplied by -1, or an irrational number with a minus sign in front of it.
At least one of the factors has to be irrational.* An irrational number times ANY number (except zero) is irrational. * The product of two irrational numbers can be either rational or irrational.