Wiki User
∙ 9y agoNo. The distance to the Moon and back is 500,000 miles, which would take 10 days (500,000 divided by 50,000), which is more than a week (7 days).
Or, to put it another way, the trip there takes 250,000 miles/ 50,000 miles a day = 5 days, so for the week you would only have 2 days left (7-5) and it takes 5 days, at the same speed, to get back.
Wiki User
∙ 9y agoNo, the spaceship would not be able to travel to the Moon and back in one week with its range limited to 50,000 miles per day. The total distance to the Moon and back is 500,000 miles, which is further than the spaceship can travel in a week.
No, it is not possible to determine the speed of someone in space based on the information given. To calculate speed, we need to know the distance traveled and the time it took to travel that distance, and in this case, we don't have either of those values. We know that one year on the spaceship is equal to 50000 years on Earth, but that does not provide us with any information about the speed of the spaceship.
It would take approximately 20 hours to travel to the moon at a speed of 50,000 km per hour. This calculation is based on the average distance from Earth to the moon, which is about 384,400 km.
Since 1 AU is the distance from the Sun to the Earth and it takes about 8 Minutes for light to travel such a distance this problem can be solved by simple multiplication and division.(50,000 AU)(8 Minutes)=400,000 Minutes/60 (Minutes/Hour)=6666.67 Hours/24 (Hours/Earth Day)=277.78 DaysSo the answer is 277.78 Earth Days or 0.76 Earth Years!
50000 hours is equivalent to approximately 2083.33 days.
This is known as the Oort Cloud, a distant region composed of icy bodies orbiting the Sun at the outer edges of the solar system. These comets are thought to originate from the early formation of the solar system and are influenced by the gravitational pull of nearby stars.
No, it is not possible to determine the speed of someone in space based on the information given. To calculate speed, we need to know the distance traveled and the time it took to travel that distance, and in this case, we don't have either of those values. We know that one year on the spaceship is equal to 50000 years on Earth, but that does not provide us with any information about the speed of the spaceship.
There will be 25 50000 scale toposheets in one 250000 scale toposheet because 250,000 divided by 50,000 equals 5, and 5 squared is 25.
0.2 * 250000 = 50000
0.2
500000
50,000
Anywhere between 50000-250000 depending on what they fly and where.
25000
46000 is nearer to 50000 than it is to 40000. So, to the nearest ten thousand 246000 becomes 250000.
50000 km
50000 miles
The distance is about 786 air miles.