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What is the molality of a solution prepared by mixing 25.0 g ethylene glycol FW equals 62.07 C2OHC2OH with 125 g of water?
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What is the correct molality of a solution prepared by dissolving 0.100 mol of chloroform CHCI3 in 400.0 g of toluene?
The correct molality of the solution can be calculated using the formula: molality = (moles of solute) / (mass of solvent in kg) Given that 0.100 mol of CHCl3 is dissolved in 400.0 g (0.400 kg) of toluene, the molality of the solution is 0.250 m.
What is the molality solution that has 3 mol of glucose in 6 kg if water?
The molality of the solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, there are 3 mol of glucose in 6 kg of water. Therefore, the molality of the solution is 0.5 mol/kg.
What is the molality of a solution that has 6 mol of cacl2 in 3kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, the molality of the CaCl2 solution would be 2 mol/kg, as 6 mol of CaCl2 dissolved in 3 kg of water results in a molality of 2 mol/kg.
What is molality of a solution that has 4 mol of KCI in 0.800 kg of water?
4 mol/0.800 kg
What is the molality of a solution made by dissolving 2 moles of NaOH in 10 kg?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, with 2 moles of NaOH dissolved in 10 kg of water, the molality would be 0.2 mol/kg.
What are the molality and mole fraction of solute in a 25.5 percent by mass aqueous solution of formic acid (HCOOH)?
The molality is 5,54.
Why molarity of a solution remains constant?
Molality of a solution remains constant as mass of a solution independent of temperature.
What is the molality of a solution in which 3.0 moles of NaCl is dissolved in 1.5 Kg of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, the moles of NaCl is 3.0 and the mass of water is 1.5 kg. Therefore, the molality of the solution is 2.0 mol/kg.
What is the molality of a solution containing 10.0g of Na2SO4 dissolved in 1000.0g of water?
To find the molality, we first calculate the moles of Na2SO4: 10.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 0.0705 moles Na2SO4. Then, molality is calculated as moles of solute (Na2SO4) / kilograms of solvent (water): 0.0705 mol / 1.000 kg = 0.0705 mol/kg, which is the molality of the solution.
What is the molality of ethanol in a solution made by dissolving 14.6 g in 53.6 g of water?
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. First, calculate the moles of ethanol using its molar mass and mass given, then convert the mass of water to kg. Finally, use the formula molality = moles of solute / kg of solvent to find the molality.
What is the molality of a solution that has 4 mol of KCl in 0.800 kg of water A.?
4 mol over 0.800 kg
What is the freezing point of a solution made by dissolving 352 g of ethylene glycol in 648 g of water?
The freezing point of the solution can be calculated using the formula: ΔTf = Kf * m. First, calculate the molality (m) of the solution by dividing the moles of solute by the mass of the solvent in kg. Then, use the molality and the freezing point depression constant (Kf) for water (1.86 °C/m) to find the freezing point depression (ΔTf). Finally, subtract ΔTf from the normal freezing point of water (0°C) to find the freezing point of the solution.
