Yes.
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The factors of 88 are 1, 2, 4, 8, 11, 22, 44 and 88.1, 2, 4, 8, 11, 22, 44, 88.
1, 2, 4, 8, 11, 22, 44, 88: (1 x 88, 2 x 44, 4 x 22, 8 x 11)
Yes, because 88 is evenly divisibly by 4. 88 divided by 4 equals 22, with 0 remainder. Since the remainder is 0, we say that 88 is "evenly divisible" by 4, and 4 "is a factor of" 88.
88 is an integer and not a fraction. It can be expressed in rational form as 88/1, but the simplest form is just 88.
1, 2, 4, 8, 11, 22, 44, 88