30, 42, and 70
As a product of its prime factors: 3*3*11 = 99
two prime numbers whose product is 141 = 3 & 47
15 is the product of two prime numbers; 3 x 5
The product of the first three prime numbers (2, 3, and 5) is 30.
30, 42, and 70
30, 42, 66, 70, 78
All the numbers less than 100 that are the product of exactly three different prime numbers are 30, 42, 66, 70, and 78. Need to know how to get the answer
Both 3 and 5 are prime numbers. 3 x 5 = 15
30, 42, 66, 70, 78
As a product of its prime factors: 3*3*11 = 99
There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)
The three prime numbers between 70 and 80 are: 71, 73, 79
How about: 2*3*5 = 30 which is the product of the 1st three prime numbers
As a product of its prime factors: 3*37 = 111
As a product of its prime factors: 3*5*5 = 75
two prime numbers whose product is 141 = 3 & 47